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A wattmeter is marked 15 A/30A, 300V/600V and its scale is marked up to 4500 watt. When the meter is connected for 30A, 1600V, the pointer indicates 2000 watts. The actual power in the circuit in
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Answer Posted / sudip saren
Power consumed(wattmeter)=ct ratio*pt ratio*vi*cos$
2000=(15/30)*(300/600)*600*30*cos$
or, cos$=0.44
P actual=VIcos$=600*30*0.44=8000w
| Is This Answer Correct ? | 46 Yes | 8 No |
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