Answer / niranjan

proportions 1:6
sum of ingredients in mortar, 1+6=7
dry material required for cement sand mortar for 1 cu mec of brick work=.30 cu mec.

cement required for 1 cu mec=1x.30/7=0.0428571 cu mec.
                             0.0428571/0.034725=1.234 bags
                                               =61.709 kg
sand required for 1 cu mec=6x.3/7=0.2571 cu mec.

Answer / mohd zubair ali

assume brick size is 19*9*9 cm. and in one cum 650 bricks ,48kg of cement and 0.2cum of sand required 
NOTE:-(amount of cement require =0.2*1440/6 = 48kg
constant proportion for sand is 1cum of cement mortar is 0.2 )

In jack arch floor, the rise is kept?

1 Answers  

---

Why we test compressive strength after 28 days..?

3 Answers   NM Caramoan Builders,

---

Why silt content not allowed more than 6% for Sand ?

2 Answers   CCEL, L&T, NTPC,

---

How many hours should traffic be not allowed after completing wbm road or bst.and min how many hours should road rollers be used.

1 Answers  

---

why we create short columns under grade slab?

1 Answers  

---

wat is the proportion of M40?

3 Answers  

---

Hi.. Can i get hel in finding HPCL previous year question paper? plz help me in finding thiss..

1 Answers   HPCL,

---

What is the use of offset command?

1 Answers  

---

How to calculate the sand and aggregate in concrete

1 Answers   DLF, OMC,

---

which type of cement uses for R.C.C. & why?

2 Answers   Ideal Construction‎,

---

what is called super elevation of the road?

1 Answers   PBL,

---

design mix for M15,M20, M25,M30 please

2 Answers   CIDC, Design Ideas,

---