Answer / dan

if (x & (x-1)) // false only if x is a power of 2

Answer / vadivel

# include <stdio.h>

void main()
{
int n;
scanf("%d",&n);
if( n & (n-1) )
printf("Not a Power of 2");
else
printf("Power of 2");
}

Answer / ataraxic

Previous post -- It's wrong... absolutely...

Answer / phil

if (x && !(x & (x-1)) == 0)

Answer / jb

(x ^ x-1) == ((x << 1) - 1)

Answer / ashutosh

I think
if (x & (x-1)) wont work when number is negative.

Answer / natmat

(~i & (i-1)) == (i - 1))

Answer / fjords

if (int(log(x)) == log(x)) // log is to the base 2

Answer / rahul priyadarshi

#define ISPOW2(x) ((x==1)?1:(x&(x-1)))?0:1

Answer / yevgen

if ((num XOR (num - 1)) == num + num - 1) return true;
else return false;

write a origram swaoing valu without 3rd variable

2 Answers  

how can i search an element in an array

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can u give me the c codings for converting a string into the hexa decimal form......

1 Answers  

main(){ unsigned int i; for(i=1;i>-2;i--) printf("c aptitude"); }

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void ( * abc( int, void ( *def) () ) ) ();

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main() { int i=1; while (i<=5) { printf("%d",i); if (i>2) goto here; i++; } } fun() { here: printf("PP"); }

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main() { int i=5; printf("%d",++i++); }

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#define max 5 #define int arr1[max] main() { typedef char arr2[max]; arr1 list={0,1,2,3,4}; arr2 name="name"; printf("%d %s",list[0],name); }

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Declare an array of N pointers to functions returning pointers to functions returning pointers to characters?

1 Answers  

Write a program using one dimensional array to assign values and then display it on the screen. Use the formula a[i]=i*10 to assign value to an element.

1 Answers   Samar State University,

main() { show(); } void show() { printf("I'm the greatest"); }

2 Answers