Answer / binil kuriachan

void main()
{
int a;
printf(" enter the values of x");
scanf("%d",&x);

if(a&1) //or if(a&(a-1)) return true if not power of 2
printf(" \n not a power of 2 ");
else("printf("power of 2");

getch();
}

Answer / anvesh t

if ((0 != n) && !(n & n-1))

Answer / diwakar

int main()
{
int x=798;
int a=0;
a=(~x)&1;
if(a)
printf("Even");
else
printf("odd");
return 0;
}

Answer / natmat

printf("%u=%u\n", x, ((x & ~(x - 1)) == x));

Answer / valli

#include<stdio.h>
main()
{
int n,c=0,i;
for(i=0;i<(sizeof(n)*8);i++)
if(n&(1<<i))
c++;
if(c==1)
printf("%d is powwer of 2",n);
else
printf("%d is not a power of 2",n);
}

Answer / xyz

main()
{

int a[30];
int i=0;
for(i=0; i<30; i++)
a[i]=i;
for(i=0; i<30;i++)
{
if(!(a[i] & a[i-1]))
printf("%d is power of 2\n",a[i]);
else
printf("%d is not a power of 2\n",a[i]);
}



}

Answer / lomesh

#include<stdio.h>

main()
{
int a;
printf("Enter the Positive Number > 0");
scanf("%d",&a);
if ((a&1)==0)
{
printf ("Number Is POWER off 2");
}
else
{
printf ("Number Is NOT power of 2");
}
getch();
}

Answer / nikos

x & (x - 1) == x + (x - 1)

Answer / sathish

main()
{
int a;
scanf("%d",&a);
if((a+(a-1))==((a<<1)-1))
printf("it is powers of 2");
else
printf("not powers of 2");
}

Answer / raghavendra donnur

#include<stdio.h>

void main()
{
int a,i;
scanf("%d",&a);

for( i = 0; a != 0; a = a >> 1)
if( a & 0x01 )
i++;
if( i == 1 )
printf ("POWER off 2");
else
printf (" Not power of 2");
}

union u { struct st { int i : 4; int j : 4; int k : 4; int l; }st; int i; }u; main() { u.i = 100; printf("%d, %d, %d",u.i, u.st.i, u.st.l); } a. 4, 4, 0 b. 0, 0, 0 c. 100, 4, 0 d. 40, 4, 0

1 Answers   HCL,

why is printf("%d %d %d",i++,--i,i--);

4 Answers   Apple, Cynity, TCS,

main() { int i; i = abc(); printf("%d",i); } abc() { _AX = 1000; }

2 Answers  

main() { int i = 257; int *iPtr = &i; printf("%d %d", *((char*)iPtr), *((char*)iPtr+1) ); }

1 Answers   CSC,

#include <stdio.h> #define a 10 main() { #define a 50 printf("%d",a); }

2 Answers  

main() { int i =0;j=0; if(i && j++) printf("%d..%d",i++,j); printf("%d..%d,i,j); }

1 Answers  

Given a list of numbers ( fixed list) Now given any other list, how can you efficiently find out if there is any element in the second list that is an element of the first list (fixed list)

3 Answers   Disney, Google, ZS Associates,

source code for delete data in array for c

1 Answers   TCS,

main( ) { void *vp; char ch = ‘g’, *cp = “goofy”; int j = 20; vp = &ch; printf(“%c”, *(char *)vp); vp = &j; printf(“%d”,*(int *)vp); vp = cp; printf(“%s”,(char *)vp + 3); }

1 Answers  

const int perplexed = 2; #define perplexed 3 main() { #ifdef perplexed #undef perplexed #define perplexed 4 #endif printf("%d",perplexed); } a. 0 b. 2 c. 4 d. none of the above

1 Answers   emc2, HCL,

main() { char name[10],s[12]; scanf(" \"%[^\"]\"",s); } How scanf will execute?

2 Answers  

Predict the Output: int main() { int *p=(int *)2000; scanf("%d",2000); printf("%d",*p); return 0; } if input is 20 ,what will be print

2 Answers