main(int argc, char *argv[]) { (main && argc) ? main(argc-1

main(int argc, char *argv[])

{

(main && argc) ? main(argc-1, NULL) : return 0;

}

a. Runtime error.

b. Compile error. Illegal syntax

c. Gets into Infinite loop

d. None of the above

Question Posted / guest

4 Answers
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main(int argc, char *argv[]) { (main && argc) ? main(argc-1, NULL) : return 0; ..

Answer / guest

b) illegal syntax for using return

Is This Answer Correct ?

17 Yes

5 No

main(int argc, char *argv[]) { (main && argc) ? main(argc-1, NULL) : return 0; ..

Answer / akshata

d. None of the above

Is This Answer Correct ?

3 Yes

4 No

main(int argc, char *argv[]) { (main && argc) ? main(argc-1, NULL) : return 0; ..

Answer / viliami

The answer is 0

Is This Answer Correct ?

2 Yes

4 No

main(int argc, char *argv[]) { (main && argc) ? main(argc-1, NULL) : return 0; ..

Answer / sushil

it will give a run time error since , return cannot be used
as it is used in ternary operator.

Is This Answer Correct ?

1 Yes

3 No

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