Answer / raghuram.a

//Simple.use recursion!
#include<stdio.h>
int f(int i,int n)
{
i<=n&&printf("\t%d",i)&&f(++i,n);
return 1;
}
main()
{
f(1,100);
return 0;
}

Answer / anil

//To print 1-50 without using any loops or condition statement
main()
{
static int i;
printf("%d \n",i++);
(i%51)&&main();
}

Answer / pree

i wnt to print 1 to 15 without using any loop,conditional
statments ,ternary operators,if conditions
nothing.........is dere any way now to print the numbers????/

Answer / uday

Console.WriteLine(
String.Join(
", ",
Array.ConvertAll<int, string>(
Enumerable.Range(1, 100).ToArray(),
j => j.ToString()
)
)
);

Answer / grasshopper

simple !
create a loop by main()

.i.e call main(previous_num) from main.

till break char is hit.

Answer / prince

main()
{
int n;
printf("enter limit:");
scanf("%i",&n);
print(n);
}

print(int n)
{
n>0?print(n-1):printf("");
printf("\n%d",n);
}

Answer / nain

plz explain above answer ......

Answer / srujana

#include<stdio.h>
void main()
{
int i=0;
printf("value of i",(i>=100)?exit(0):i);
i++;
continue;
}
OR
by using recursion
#include<stdo.h>
int rec(int i)
{
if(i>=100)
return;
else
i++;
return i;
}
void main()
{
rec(1);
}

Answer / srividhya

#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
void main()
{
int i=0,n,x;
scanf("%d",&n);
label1:
{
printf("%d",i);
i++;
x=i<n?i:0;
exit(x);
continue;
}
getch();
}

Answer / akshay babar

#include<stdio.h>
int print(int i)
{
if(i>0)
return print(printf("%d", i--));
else
return 1;
}
main()
{
print(100);
return 0;
}

Write a routine to draw a circle (x ** 2 + y ** 2 = r ** 2) without making use of any floating point computations at all.

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