Answer / 7anoter4

1)If this is only 1 capacitor and this is the voltage
between capacitor terminals:

Cap=10^9*Q/(Voltage^2*2*pi*frequency) if Q is in kVAR and
capacity in microFarad.

pi=3.14159

Cap=10^9*12.5/(440^2*2*pi*50)=205.5 mF

2)If this is reactive power of 3 capacitors in Y connection:

Voltage at a single capacitor terminals will be 440/sqrt(3)
=440/1.73=254 V

Reactive power of a single capacitor will be 12.5/3=4.167
kVAR

Then the capacity of a single capacitor will be :

Cap=10^9*4.167/(254^2*2*pi*50)=205.5 mF

3)If this is reactive power of 3 capacitors in Delta
[Triangle] connection:

Voltage at a single capacitor terminals will be 440 V

Then the capacity of a single capacitor will be :

Cap=10^9*4.167/(440^2*2*pi*50)=68.5 mF

If Q=25 kVAR Voltage=440 V then the capacity of a single
capacitor will be :

single and Y=411 microF ; Delta=137

If Q=12.5 kVAR Voltage=690 V then the capacity of a single
capacitor will be :

single and Y= 83.6 microF ; Delta=27.85

If Q=25 kVAR Voltage=690 V then the capacity of a single
capacitor will be :

single and Y= 167 microF ; Delta=55.7 microF

is electrons really flow or they just vibrate at their position?

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