Answer / idiot4ever

Resistance of the bulb element has to remain same for given
room temperature. so, for a resistive element like bulb,
P = (V^2) / R ; hence R = (V^2)/P.

The brightness depends on current and hence the power.

R remains constant. so ,
P (new) = P (old) * V(new)^2 / V(old) ^2
V (new) < V (old) , hence power output is reduced.

So it will be less bright.

Answer / .

Brightness will less

Answer / shri

Brightness will little bit more

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