how does an EDM works?
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Answer / hanumanth
Wire EDM machining (Electrical Discharge Machining) is an
electro thermal production process in which a thin single-
strand metal wire in conjunction with de-ionized water
(used to conduct electricity) allows the wire to cut
through metal by the use of heat from electrical sparks.
Due to the inherent properties of the process, wire EDM can
easily machine complex parts and precision components out
of hard conductive materials.
| Is This Answer Correct ? | 8 Yes | 0 No |
Answer / praveen
Electric discharge machining (EDM), sometimes colloquially also referred to as spark machining, spark eroding, burning, die sinking or wire erosion,[1] is a manufacturing process whereby a desired shape is obtained using electrical discharges (sparks).[2] Material is removed from the workpiece by a series of rapidly recurring current discharges between two electrodes, separated by a dielectric liquid and subject to an electric voltage. One of the electrodes is called the tool-electrode, or simply the ‘tool’ or ‘electrode’, while the other is called the workpiece-electrode, or ‘workpiece’.
When the distance between the two electrodes is reduced, the intensity of the electric field in the volume between the electrodes becomes greater than the strength of the dielectric (at least in some point(s)), which breaks, allowing current to flow between the two electrodes. This phenomenon is the same as the breakdown of a capacitor (condenser) (see also breakdown voltage). As a result, material is removed from both the electrodes. Once the current flow stops (or it is stopped – depending on the type of generator), new liquid dielectric is usually conveyed into the inter-electrode volume enabling the solid particles (debris) to be carried away and the insulating proprieties of the dielectric to be restored. Adding new liquid dielectric in the inter-electrode volume is commonly referred to as flushing. Also, after a current flow, a difference of potential between the two electrodes is restored to what it was before the breakdown, so that a new liquid dielectric breakdown can occur.
| Is This Answer Correct ? | 3 Yes | 0 No |
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