Calculate the line size for a cooling water line with a
volumetric flowrate of 1200m3/h of water. Density of water =
1000kg/m3
Answer / Ashish Maurya
First, calculate the mass flow rate (F) using the given density (rho) and volumetric flow rate (Q): F=ρ*QnF=1000 kg/m^3 * 1200 m^3/h = 1.2E6 kg/hnNext, find the cross-sectional area (A) of the pipe by considering the desired velocity (V). For cooling water lines, a typical velocity ranges from 0.5 to 4 m/s.nAssuming V=2 m/s and using the formula A=F/(ρ*V), we get:nA = 1.2E6 kg/h / (1000 kg/m^3 * 2 m/s) = 0.6 m^2nSince the standard pipe sizes are usually in multiples of 0.0254 m^2 (or sq ft), you may choose a pipe with approximately 0.61 sq ft or a diameter of around 7.9 inches.
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Question 62 – The names of the flow streams could be represented by : H1 for first hot stream, H2 for second hot stream, C1 for first cold stream, C2 for second cold stream. Data of supply temperature Ts in degree Celsius : 150 for H1, 170 for H2, 30 for C1, 30 for C2. Data of target temperature Tt in degree Celsius : 50 for H1, 169 for H2, 150 for C1, 40 for C2. Data of heat capacity Cp in kW / degree Celsius : 3 for H1, 360 for H2, 3 for C1, 30 for C2. (a) Find the enthalpy changes, dH for all streams of flow H1, H2, C1 and C2 in the unit of kW. Take note of the formula dH = (Cp) (Tt - Ts). (b) Match the hot streams H1 and H2 with the suitable cold streams C1 and C2 to achieve the maximum energy efficiency.
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