Answer / heamnth

the minimum fludisation veocity is the velocity of the gas
or liquid at which the bed pressurecdrop in the bed equals
to the weight of the bed.

Answer / sujeetha

the superficial fluid velocity at which the upward drag
force exerted by the fluid is equal to the apparent weight
of the particles in the bed".

Answer / akhil

minimum fluidization velocity is the superficial velocity of
the fluid in a fluidized bed at which the drag force by the
upward moving fluid is equal to the weight of the solid
particles.

Answer / rajesh kumar bhagat

for minimum fludization velocity we increase the flow of fluid
in the bed to be fludized. then let the bed Seattle and re-
increase the flow rate of fluid, the minimum velocity at which
bed re-fludized is called minimum fludization velocity.
theoritically it can be determined by erguen equation or buke
pulmer equation.

Answer / deepak

Minimum fluidization velocity is that,the pressure drop across the bed must be equal to the effective weight per unit area of the particles at the point of incipient fluidization.

Answer / swaraj panda

superficial velocity at the point of fluidization is known as minimum fluidization velocity

Answer / pradeep

minimum fluidization velocity can be defined as the velocity
at which the pressure drop reaches to maximum,at that point
the velocity is called as minimum fluidization velocity

Answer / mustaqeem ali khan

when frictional forces counter the gravitational forces then it is called monimum fludization

Answer / giri

the velocity where true fluidisation will begins

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0 Answers  

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hello sir..iam keen to sit for iocl interview..please forward sample iocl questions to my id: kunal_kv06@yahoo.co.in

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DIFFERENTIAL EQUATIONS - EXAMPLE 20.1 : By using Excel program either on laptop or desktop PC, solve the differential equation dy / dx = -2y + x + 4 with h = 0.005, initial values : x = 0, y = 1. The 4th order Runge-Kutta method provides : y(N + 1) = y(N) + (1/6) (k1 + 2k2 +2k3 + k4), k1 = h [ -2y(N) + x(N) + 4 ], k2 = h { -2 [ y(N) + k1 / 2 ] + x(N) + h / 2 + 4 }, k3 = h { -2 [ y(N) + k2 / 2 ] + x(N) + h / 2 + 4 }, k4 = h { -2 [ y(N) + k3 ] + x(N) + h + 4 }. What is the value of y at x = 0.5?

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