a bottle of concerntrated HCL (36.5) was labelled as 37%
(w/w) and density 1.19m/l.What is hcl molarity?
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Answer / umesh patel
the molarity of the resultant solution will be around 12
|Is This Answer Correct ?||50 Yes||5 No|
Answer / mandal
calculate mass for 1L of Hcl
1.19*1000= 1190g . 1190 g of entire solution 37% is Hcl- hence
37/100*1190= 440.3 g is Hcl
M= mole/L = W/mw*1L= 440.3/36.5*1L= 12.06 M
|Is This Answer Correct ?||33 Yes||5 No|
Answer / dave
37% (w/w) implies 37g of HCl in 100 g of solution.
37g is 37/36.5 = 1.01 moles HCl.
However, this is dissolved in 100 g of solution not 100 mL of solution. The actual volume present can be determined from the density of 1.19 g/mL.
100 g/V mL = 1.19, therefore the actual solution volume is 100/1.19 = 84 mL.
The concentration is 1.01/84 mol/ml = 0.012 mol/ml
Or, in mol/L this is 1000 x 0.012 = 12 mol/L.
If this had been 37% (w/v) this would have been 37 g HCl in 100 mL solution and no correction for density would have been needed. The concentration in that case would have been 10.1 mol/L
|Is This Answer Correct ?||8 Yes||0 No|
Answer / sagar pawar
Where V=Volume,B=Basicity, P=Purity, D=density
m= Molecular wt.
= 12.06 M
|Is This Answer Correct ?||13 Yes||6 No|
Answer / shashi
|Is This Answer Correct ?||7 Yes||4 No|
Answer / gursharn singh kang
molarity =( given percentage *density/molecular wt.)*10
so M WT. of hcl=36.46
|Is This Answer Correct ?||0 Yes||0 No|
Answer / bujji kanchi
37% means 37 g of solute dissolved in 100 ml solvent.
37g/100 ml= 10 N
|Is This Answer Correct ?||3 Yes||14 No|
Answer / shashi
Strength = %assay*density*100/mol wt* 1000
|Is This Answer Correct ?||4 Yes||28 No|
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