Answer / k.prakashchandra

In case of load,it will result in negative voltage
regulation increasing the voltage.In case of generators it
has the de-stablizing effect on the system ,the pf of which
is always lagging.

Answer / g.tripathi

It will have negative voltage regulation effect generating
high voltage spikes on the load.Moreover it will again
increase the current of the system which will result in
more power loss

Answer / pandu

the main disadvantage of leading power factor is wating the
power

Answer / yawista

sir can you please explain further...what is wating the power?

Answer / k. s. rajiv

It results negative voltage regulation,again decreases
pf,high current,voltage spikes,power loss etc. In short all
these adversely affect load and network. So connect
capacitors individually to the load so as to be isolated it
whenever the load is turned off.

Answer / romroxmal

It's unpractical to have a leading power factor in an
electrical distribution system in general because majority
of your loads especially motors and some rotating machines
are partly inductive loads. Just keep the power factor
lagging like 85 to 95% PF by automatic capacitor banks.
Efficiency and life expectancy of those said loads mentioned
will be diminished.

Answer / n.silambarasan

the leading power factor is not used in resistive load
accept reactive power.the inductive load only need the
reactive power

Answer / guest

actually We cannot use the pf=0 , at least it should be some value. i mean to say,0.x to 1,
0.1 0.3 0.5 0.7 0.9 1 0.9 0.7 0.5 0.3 0.1
Lagging-> Unity <-Leading

Actually there are three power generated in an electrical system.
1. Active, real or true power which are expressed in kw = sqrt(3)*v*I*cosØ
2. Apparent power expressed in kva = sqrt(3)*v*I
3. Reactive Power expressed in kvar = sqrt(3)*v*I*sinØ
If cosØ(power Factor)=0.99 or -0.99, the sinØ will be same=0.14
If cosØ=-0.8 or 0.8, the sinØ will be same=0.6
If cosØ=-0.5 or 0.5, the sinØ will be same=0.86
According to the above values it is clear that if we go for lagging or leading pf the reactive power generated will be equal.
Kva= kw+kvar,
If use lagging or leading pf the real power (kw)we can use is same. So we must go for nearest value to unity pf to make Kva=kw(this condition satisfies only if Kvar=0 and pf=1) Finally more real power usage.
Then one of my friend told govt is advicing them to use leading power factor , its only because apart from the bulk consumers the domestic users wont use pf correction. In order to compensate we are said to use leading pf.

Answer / shareef

P= SQRT(3) * V * I * P.F
P.F= Cosin(AN)
AN= angle between V&I

If you are talking about P.F that means you are talking
about loads.
1- If P.F=1 that means the load is resistive load (its the
ideal case, the consumed power is active power only: MW)

2- If P.F=0 that means the load is inductive or capacitive
-(If the power is inductive that means the load will
consume power: +MVAR)
-(If the power is capacitive that means the load will
deliver power to the system: -MVAR)

In electrical systems the loads are resistive and reactive
that means the P.F value will be between 0 & 1

Examples
* If P.F = 0.9, its good for electrical system because it
is nearset the ideal case (the Voltage drop is less & the
voltage at end bus is within the limits)
* If P.F = 0.6, its bad for electrical system (the Voltage
drop is high & the voltage at end bus is out oflimits), in
this case we need to install capacitor bank to improve the
P.F and the voltage at end bus

Note. capacitor bank will deliver/give MVAR to the
electrical system

Answer / m.s.kailash

In practically it is not possible(i.e.power factor=0).If
Theoretically power Factor=0,means there is no actual
power(true power).(i.e.only wastage of power).
i think your i question is wrong pf=0 means lagging power
factor.
there is no disadvantage of leading power factor.
if lagging power factor means more wastage of power

i need the curve duty cycle and amper for (150 kva @50% dyty cycle) transformer turn ratio :19 and vin 400

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