Answer / jayavijayan k

SILT Content in Sand should not be more than 7% by Volume.
( means upto 7% can be used without Washing).

Silt content of a Sand is meaured by folllowing
Procedure,
a) Take a clean 200ml. measuring jar
b) Fill with sand upto a certain mark ( say reading 'X')
and add water above it upto 200ml. and shake well.
c) Allow a period of 2hours for settlement
d) Clean sand will settle at the bottom with silt and clay
impurities on top of the sand layer.
e) Now oserve the top level reading for sand. Assume that
is 'Y'. Then the silt contain in % is given by,
% Silt content = (X-Y/X)*100

Answer / naresh

(X-Y/Y) * 100

Answer / dharmendra

x is the initial mark , but after adding water and waiting
for 1 hr then we have to take the SAND+SILT = A ml , and
then the only sand level say B ml

silt content = (A-B)/B *100


AND (X-B)/B*100 is BULKING OF SAND

Answer / sathish

IS code 383 Reference

Maximum allowed for 3% in wet sieve analysis method

75 micron sieve ..used

example
wet sand samle oven heat by process
Then Dry sand 500 gms
IS sieved 75 micron
same value reduce 478
= 500-478 =22
=22/478*100
=4.60%

Answer / qc

I want to know one what is (SILT Content in Sand should not
be more than 7% by Volume.) reference is where?
ACI ASTM or BS?
What?

Answer / manjeet ahlawat

it should be (A-B)/B*100

Answer / shubhangi gosavi

It should be (y-x)/x * 100

Answer / idrees jae

yeah,i am of the opinion that answers 1 and 2 are correct depending on the perspective.
answer 1,gives you the actual % of silt while answer 2 gives you the worse case.

How we can calculate the quantity of sand, & cement, & also aggregate for a slab. Length 25'/3.28 = 7.62 Mtr width 20'/3.28 = 6.09 Mtr depth 6" /3.28 = 0.152 Mtr

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