Answer / will

Say cement sand ratio is 1:6
calculate the quantity of mortar in 1m2 of brickwork, say
it is 0.01912.
just devide by the ratio considering 60% for wastage, say
0.01912/1*0.6=0.01147 volume of cement in the mortar.
Divide the total volume of cement by 0.0345 which s the
volume of 1 bag, say 0.01147/0.0345=0.33257/m2*number of
m2, say 100m2=34bags.

Answer / dilshad akthar

ratio: 1:4
for 1 m3,cement= 1/(1+4)=1/5=.2m3,let it be .2+.6*.2=.32
quqntity of cement:


.32*1440(unit wt of cement)*1=460.8

bags rqd= 460.8/50(1 bag)=9.2````let be 10;


sand requred

4*.2*1=.8m3



typical one load==5m3

Answer / t.chandrasekar

the unit weight of cement is 1440kg/m3.
for 1 m3 of 1:1 cement mortor the reuirement of sand is 1m3
and cement will be 1part of sand that is 1 m3 thus weight
of cement required is 1x1440kg/m3=1440 kg.
for 1 m3 of 1:2 cement mortor the reuirement of sand is 1m3
and cement will be 1/2 part of sand that is 0.5 m3 thus
weight of cement required is 0.5x1440kg/m3=720 kg.
for 1 m3 of 1:4 cement mortor the reuirement of sand is 1m3
and cement will be 1/4 part of sand that is 0.25 m3 thus
weight of cement required is 0.25x1440kg/m3=360 kg.
for 1 m3 of 1:6 cement mortor the reuirement of sand is 1m3
and cement will be 1/6 of part sand that is 0.5 m3 thus
weight of cement required is 1/6x1440kg/m3=240 kg.

Answer / kamlesh patidar

in cement morter the void between sand and cement is less
and take 25% total wet volume of water.take 10 cu m wet
volume of morter increse 25% than total volume of dry
material 12.5 cu m . if we find the material in 1:6 morter
than 12.5/(1+6)
cement=1.78 cu m sand=1.78*6=10.71cu m

Answer / syed mahaboob hussain

the procedure to calculate quanity is given below

RATIO (1:6)

NOTE = 1:6: 0.55(Water) = + (7.55)

CEMENT = 1m3/7.55 x 1 = 0.132m3 (No of Kg = 0.132 x 1506 =
198.792kg)

Sand = 1m3/7.55 x 6 = 0.794m3 (No of Kg = 0.132 x 1650 =
437.250 kg)

Water = 1m3/7.55 x 0.55 = 0.072 m3 ( No of Kg = 0.072 x
1000 = 72liter)

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