how to calculate 1:2:4 ratio concrete cement, sand, metal
and water please give me brief calculation
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Consider for 1CUM of concrete is to be prepare,For that
M15 is a nominal mix, its proportion is 1:2:4
for 1cum of final mix(Dence) is required, 1.50 to 1.55 Cum
of loose ingredients with the required proportion we want
to add.
Based on that take avg of 1.50 & 1.55 is 1.52
Total proportion = 1+2+4 = 7
For Cement Qty = 1.52/7=0.217 Cum of cement required to
prepare 1Cum of M15 concrete.But cement is always taken in
Weight.For that the unit weight of cement is 1440 KG/Cum
Total cement required = 0.217x1440= 312.68 Kgs.
Sand = 0.217 x 2 =0.434 Cum
Metal or Aggregate = 0.217 x 4 =0.868 Cum.
Is This Answer Correct ? | 1120 Yes | 173 No |
Answer / adishankar (quantity surve
DETAILS:
cement = 1,
sand = 2
metal = 4
so wat is the ratio we want mixing (1:2:4)=1+2+4=7
7 is mixing propotion
volume of wet cement conceret is 1.54 to 1.57
unit weigth of cement is 1440kg/cum
one bag of cement =50/1440=0.034722 cum
solution : cement = 1.54/7=0.22
0.22/0.03472=6.33 bags
one bag of cement = 50kgs
=6.33*50kgs=316.82 kgs
solution of sand = 0.22*2=0.44cum
2 is the mixing of propotion
soolution of metal = 0.22*4=0.88cum
4 is the mixing of propotion
say i cum of cement conceret 1:2:4 ratio
cement = 6.33 bags
sand = 0.46 cums
metal = 0.88 cums
this is one type of solution
unit weight of cement is 1440kg/cum
sand 1660 to 1800kg/cum
Unit weight of metal is 1630kg to 2000kg/cum
so cenment = 1.54/7=0.22
0.22*1440=316.8 kgs/cum
sand = 0.22*1750=385kgs/cum
metal = 0.22*2000=440kgs/cum
Is This Answer Correct ? | 554 Yes | 92 No |
Answer / pinkal
Here volume is (1 cement bag=1.25 cu.ft)
cement 1 1.25 cu.ft
sand 2 2.50 cu.ft
metal 4 5.00 cu.ft
-----------
8.75 cu.ft total volume
Is This Answer Correct ? | 716 Yes | 336 No |
Answer / raja babu.k
Sample = 1 M3 of M15 i.e 1:2:4
Aggregate = 20mm
Final Mixture and Loose Aggregate Ratio is 1.57(in practies)
SO CALCULATION FOR 1:2:4
1+2+4=7
CEMENT = (1.57/7)X1=0.2242 M3X1440=322.8Kg= 6.45 Bags
RIVER SAND= (1.57/7)X2=0.4485 M3X35.314 = 15.83 Cft
AGGREGATE = (1.57/7)X4=0.8971 M3X35.314 = 31.68 Cft
Is This Answer Correct ? | 220 Yes | 43 No |
Answer / sjtbehera
The ratio is 1:2:4, so total ratio is 1+2+4=7
considering 1cum.
cement = (1 x 15.4)/7= 2.2 cum
= 2.2/.347=6.3bags
sand=2.2x2=4.4cum
metal=2.2x4=8.8cum
Is This Answer Correct ? | 380 Yes | 252 No |
Answer / arun
DETAILS:
cement = 1,
sand = 2
metal = 4
so wat is the ratio we want mixing (1:2:4)=1+2+4=7
7 is mixing propotion
volume of wet cement conceret is 1.54 to 1.57
unit weigth of cement is 1440kg/cum
one bag of cement =50/1440=0.034722 cum
solution : cement = 1.54/7=0.22
0.22/0.03472=6.33 bags
one bag of cement = 50kgs
=6.33*50kgs=316.82 kgs
solution of sand = 0.22*2=0.44cum
2 is the mixing of propotion
soolution of metal = 0.22*4=0.88cum
4 is the mixing of propotion
say i cum of cement conceret 1:2:4 ratio
cement = 6.33 bags
sand = 0.46 cums
metal = 0.88 cums
this is one type of solution
unit weight of cement is 1440kg/cum
sand 1660 to 1800kg/cum
Unit weight of metal is 1630kg to 2000kg/cum
so cenment = 1.54/7=0.22
0.22*1440=316.82 kgs/cum
sand = 0.44*1750=770kgs/cum
metal = 0.88*2000=1760kgs/cum
Is This Answer Correct ? | 92 Yes | 21 No |
Answer / sandeepthakur1981
for 01 cu.m.
cement=1.52/7 =.217
= .217x30= 6.51 bags.
sand= .217x2= 0.434cu.m
aggregate= .217x4= 0.868cu.m
Is This Answer Correct ? | 94 Yes | 35 No |
Answer / the engineer
In order to estimate the quantity of loose materials to have
100 cubic feet wet concrete we first multiply the wet
concrete by 1.54.
e.g 100x1.54=154 cubic feet of dry materials we need.
now come to the ratio of concrete which is 1:2:4 so sum of
the ratio will be 1+2+4=7
calculating separately each material:
Cement: 1/7x154 = 22 cubic feet
where 1 bag of cement measured 1.25 cubic feet approx
therefore 22/1.25 = 17.6 bags of cement. 1 bag contains 50kg
cement so total cement by weight we need for 100 cubic feet
concrete = 17.6x50 = 880kgs
sand: 2/7x154 = 44 cubic feet
coarse aggregate: 4/7x154 = 88 cubic feet
Is This Answer Correct ? | 59 Yes | 15 No |
Answer / m
ratio is 1:2:4
1+2+4=7
100cft concrete
100*1.54=
then divide by 7
then divide by 1.25 you wil have cement bag
Is This Answer Correct ? | 71 Yes | 29 No |
Answer / chetan khairnar
Note: For 1m3 wet concrete = 1.52m3 dry concrete approximately
SP.Wt of concrete= 1440 kg/m3 (or) 1.44 t/m3
1 bag of cement = 50 Kg
Example:- for 20 m3 volume of concrete.
a) Quantity of cement required = (1:2:4)
=1/(1+2+4) x 1.52 × 20 = 4.14m3 x 1440/50 =119.26 bags
b)Quantity of Sand required = (1:2:4)
=2/(1+2+4)×1.52x20=8.28m3 OR =4.14 x 2=8.28 m3.
c)Quantity of course aggregate = (1:2:4)
=4/(1:2;4) x 1.52 x20 = 16.56m3 OR =4.14 x 4= 16.56m3.
If qty. calculate in Kg just multiply by its Sp. wt of sand
or aggregate.
Is This Answer Correct ? | 68 Yes | 28 No |
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