Answer / Priyom

Newton's method for finding the square root of a number involves using the formula: x(n+1) = (x(n) + a/x(n))/2, where x(n) is the nth approximation and a is the number we are trying to find the square root of. In this case, a is 2. Starting from x0=1, we get:n- x1 = ((1+2)/2) = 1.5n- x2 = ((1.5 + 2/1.5)/2) = 1.416667nSo, after two iterations, our approximation for sqrt(2) is 1.416667.

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