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if we have a job consist of two steps and each step calling
a proc having 10 steps each then how many steps are counted
only 2 or 22(10+10+1+1)? can we have more than 255 steps in
a single job?
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Answer / sarath sasidharan
i can expalain you this is an easiy question you have only
one job okey, it consists of two steps then calculate (2+
then it is telling nthat each two steps consists of 10 ie
10*2=20 steps,so 20 + 2 =22 steps correct answer
| Is This Answer Correct ? | 6 Yes | 2 No |
Answer / vinod
the no of steps counted are 22 .
if we want to code more than 255 exec the split the jcl to
two and immediate after completion of one check the return
code and intialize to second one .in this way we can
perform.
i think
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / reddy kanupuru
the total no of steps are 22 only.
The job should not consists of more than 255 steps.
(includes the proc steps also)
correct if i am wrong
| Is This Answer Correct ? | 2 Yes | 2 No |
Answer / sridharaadi
The steps conted: 2
we can not have more than 255 steps in a job.
Cheers,
Aadi
| Is This Answer Correct ? | 8 Yes | 10 No |
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