write a program to accept 2 numbers from user calculate sum of each digit,reve

write a program to accept 2 numbers from user calculate sum
of each digit,reverse the orignal number and display

Question Posted / prathamesh

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write a program to accept 2 numbers from user calculate sum of each digit,reverse the orignal numb..

Answer / raja mansoor

#include<stdio.h>
#include<conio.h>
Void main ()
{
Int x, y;
Printf (”Enter two numbers”);
Scanf (“%d %d, &x, y);
1. Addition
2. Subtraction
3. Multiplication
4. Swapping the values
5. Reverse order”;
Getche () ==c;
Switch(c)
{
Case 1: sum=x+y
Printf (“%d”, sum);
Case 2: sub=x-y;
Printf (“%d”, sub);
Case 3: pro=x*y;
Printf (“%d”, pro);
Case 4: swap=x;
Printf (“%d”, x=y);
y=swap;
Printf (“%d %d”, x, y);
Case 5: while(x/10! =0)
{
N++;
}
For (i=1; i<=n; i++)
{
Printf (”Reversed of x is %d=”);
r=x%10;
Printf (“%d”, r);
x=x/10;
}
While(y/10! =0)
{
N++;
}
For (i=1; i<=n; i++)
{
Printf (”Reversed of y is %d=”);
r=y%10;
Printf (“%d”, r);

]
y=y/10;
}
Default: break;
}
Getch ();
}

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write a program to accept 2 numbers from user calculate sum of each digit,reverse the orignal numb..

Answer / amol

Void main()
{
Int x,y
Cout<<”enter two nos”
Cin>>x>>y;
Cout<<”Menu”<<endl;
Cout<<” 1. Addition 2. Subtraction 3. Multiplication 4.
Swapping the values 5. Reverse order”;
Cin>>c;
Switch(c)
{
Case 1: sum=x+y
Cout<<sum;
Case 2: sub=x-y;
Cout<<sub;
Case 3: pro=x*y;
Cout<<pro;
Case 4:swap=x;
x=y;
y=swap;
cout<<x<<y;
case 5: while(x/10!=0)
{
n++;
}
For(i=1;i<=n;i++)
{
Cout<<”reversed x=”;
r=x%10;
Cout<<r
x=x/10;
}
while(y/10!=0)
{
n++;
}
For(i=1;i<=n;i++)
{
Cout<<”reversed y=”;
r=y%10;
Cout<<r
y=y/10;
}
Default: break;
}
Getch();
}