9 balls are there one of them is of higher wt and remaining
all are of same. given is one weighing scale and you can
use it two times. How will you find the heavy ball in two
trials only.
Answers were Sorted based on User's Feedback
Answer / anand.s
1)take any 6 balls.keep 3 balls in one side and other 3
balls in other side.if there is a heavy ball in any one of
these six balls then the weigh will come down one side.goto
step 3.
2)if the weigh is equal then the heavy ball is in the
remaining 3 balls.goto step 4.
3)take those 3 balls which is on heavy side.
4)keep one ball aside and put 1 ball each in either side of
weigh.if there is heavy ball then it will come down and we
can find out.if the weigh is equal then the ball kept aside
is the heavy ball.
Is This Answer Correct ? | 107 Yes | 7 No |
Answer / murali
before weighing
divide 9 balls into 3groups contains 3 nos of balls.
weigh any 2 groups_ so u can find the odd group in first time.
choose any 2 balls from that odd group_ then u can get the
most weighed ball easily
Is This Answer Correct ? | 24 Yes | 5 No |
Answer / marx
1 Trial:
Take 3 set of 3balls and first compare any 2
set.They may are may not be equal.If thet are equal keep
these 2 sets aside and go to second trial with the 3rd set.
If they r not equal,go to second trial with the set of more
weight.
2 Trial:
Split the taken set of 3 balls in to 3 set of single
balls.Compare any one sets first.If they are equal we can
find the left out ball is of more weight.If not equal we
can find the most weight ball.
Is This Answer Correct ? | 9 Yes | 3 No |
Answer / kishore.rkv@gmail.com
make it into 3 sets each contains 3 balls, compare any two sets with the help of balance, if any one of the set is heavy then it is taken otherwise remaining set is taken, and take two balls from that heavy set and compare them, the heavier will be the final or if both are same then other one is the heavier ball.
Is This Answer Correct ? | 2 Yes | 0 No |
Answer / kunal kapoor
start putting balls 1 by 1 on the weighing scale. note down the weight of the first ball, then sec. then third and so on.If the first ball is of same wt category as that of remaining 7 the we shall be getting a constant margin everytime we put new ball but if at any stage after counting margin, it comes diff then we shall be concluding that as the heaviest of all.
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / k.shunmugaperumal
Now in market we have a higher wt indication weighing
scale,that will helpful to find out the higher wt ball form
the 9 balls. so we don't go to the second time. we find out
the odd one out from the 9 balls at the first trials.so
that weighing scale is i mentioned weighing scale?
Is This Answer Correct ? | 1 Yes | 2 No |
Answer / varun sangwan
first make 3 ball groups, and then compare any two group.
we can detect the heavier group easily and then from the
heavier group select two balls and compare their weight and
if weight found same then 3rd ball is faulty otherwise we
can found by looking at weighing scale.
Is This Answer Correct ? | 0 Yes | 2 No |
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