Source schema has nodes First Name, Last Name and
destination schema has node Name. How we can get data at
destination so that we can have two instance of Name
(without using orchestration).
Answers were Sorted based on User's Feedback
Answer / luigip
1) Build the map. The logic on how you get a single name is
not clear... Can be First Name concatenated with Last Name
(so simply use the string concatenate functoid adding a
space in between the fist and last name)
2) Create a receive port + Receive Location (name as RecLoc)
3) Create a send port
4) On the send port configure the map
5) On the send port add a filter where Receive Port Name is
equal to RecLoc
| Is This Answer Correct ? | 1 Yes | 3 No |
Answer / rajesh gorla
Ok, this is something like mapping flat source schema to
multiple occurrences of node in destination schema, use
Table Looping, Table Extractor functiond's and map. for
more info read this interesting article.
http://geekswithblogs.net/evankoch/archive/2007/08/07/114470
.aspx
| Is This Answer Correct ? | 3 Yes | 6 No |
Answer / sandeep
Create a MAP in Biz talk and add first name and last name
strings with space in between and map to destination schema
node. Use that map in port to port binding either in recieve
port or in send port.
| Is This Answer Correct ? | 6 Yes | 11 No |
Answer / navneet
Use the looping functoid to link FirstName and LastName to
Name. use this map as outbound map in send port binding.
| Is This Answer Correct ? | 2 Yes | 10 No |
What are Host and Host Instance?
I have a receive port and send port whose message types are different.When I receive a message in my receive port,my process starts.I will construct my out message and give this to my send port.I am configuring a send port group to the logical send port.TO the send port group I have added many send ports with filters.The message in the send ports are not getting filtered based on my filters. Help will be highly appreciated. Thanks in advance
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