Source schema has nodes First Name, Last Name and
destination schema has node Name. How we can get data at
destination so that we can have two instance of Name
(without using orchestration).
Answer Posted / navneet
Use the looping functoid to link FirstName and LastName to
Name. use this map as outbound map in send port binding.
| Is This Answer Correct ? | 2 Yes | 10 No |
Post New Answer View All Answers
Difference between Biztalk server and web services?
Explain why messages are immutable inside biztalk?
What are the components of biztalk server architecture?
Is there any possibility in the biztalk FIFO(first-in-first-out) without use the orchestration? how to implement explain?
i have one applition in biztalk, how to run anohther server
List out some artifacts of biztalk server? : biztalk server
What is the difference between a document schema and a property schema? : biztalk server
Explain about biztalk server messaging services?
What is convoy sets?
What is the default mapping for auto mapping? : biztalk server
What is bam?
what is direct binding?
What is the rules engine?
What is custom pipeline?
I have a receive port and send port whose message types are different.When I receive a message in my receive port,my process starts.I will construct my out message and give this to my send port.I am configuring a send port group to the logical send port.TO the send port group I have added many send ports with filters.The message in the send ports are not getting filtered based on my filters?