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There are five thieves, each loot a bakery one after the
other such that the first one takes 1/2 of the total no.
of the breads plus 1/2 of a bread. Similarly 2nd, 3rd,4th
and 5th also did the same. After the fifth one no. of
breads remained are 3. Initially how many breads were there?
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Answer / risha ramanathan
Let x ne the total no. of bread
1st thief loots : x/2+1/2 = (x+1)/2
2nd thief loots : 1/2((x+1)/2) = (x+3)/4
3rd thief loots : 1/2((x+3)/4) = (x+7)/8
4th thief loots : 1/2((x+7)/8) = (x+15)/16
5th thief loots : 1/2((x+15)/16) = (x+31)/32
now the no. of bread left is (x+31)/32
since (x+31)/32 = 3
therefore x = 65.
| Is This Answer Correct ? | 5 Yes | 23 No |
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