Answer / gaurav sharma

127

Answer / anbu

Friends,
The Answer given by 'Gaurav Sharma' is correct and
the approach (bottom to top) suggested by 'Shailesh' is
good. But with minor correction we can arrive the solution
using this approach:

After 5th loot, No. of breads left = 3
after 4th loot, no. of breads left = (3+0.5)x2 = 7
after 3rd loot, no. of breads left = (7+0.5)x2 = 15
after 2nd loot, no. of breads left = (15+0.5)x2 = 31
after 1st loot, no. of breads left = (31+0.5)x2 = 63
So, before 1st loot, no. of breads left = (63+0.5)x2 = 127

Answer / guest

127 is the correct answer.
When the last thief comes the number of bread will be 7.
Later on going upwards it takes the formula
2x+1 ie 2*7+1 =15 no will be there when Fourth thief comes
and so on.
for third thief 2*15+1 ie 31 bread will be there
for second thief 2*31+1 ie 63 bread will be there
for first thief 2*63+1 ie 127 bread will be there

Answer / guest

31

Answer / jay singh

64

Answer / randheer chauhan

3---> 3*2+0.5=6.5 ----> 6.5*2+0.5=13.5 ---
---> 13.5*2 + 0.5=27.5 ----> 27.5*2+0.5=55.5----
---> 55.5*2=111

Answer / shailesh

guyz its better to go bottom to top in this prob
After 5th man 3 bread remained implies twice no. of (breads
minus half) available b4 him
there are (3-0.5) x 2 = 5 breads available before him
for 4th man
(5-0.5)x2=9
for 3rd man
(9-0.5)x2=17
for 2nd man
(17-0.5)x2=33
for 1st man
(33-0.5)x2=65
dats total 65 breads available

Answer / j

when the fifth one take half of the total no of breads and
1/2 of a bread, it cant be the remeining no of bread is 3

Answer / chandra prakash garg

I think initialially total bread were 225.

How:

Let it be x.

(x+1)/2 + (x+3)/4 + (x+7)/8 + (x+15)/16 + (x+31)/32 + 3 = x.

Solve the equation, you will get the answer.

Answer / niraj

remaining bread= 3
5th thief loot 1/2totatl no of breads & 1/2 of bread
means breads were 3+3+1/2=6&1/2
similarly
4th thief loot 6.5+6.5+.5=13.5
3rd 13.5+13.5+.5=27.5
2nd 27.5+27.5+.5=55.5
so at the time of 1st thief
no. of breads were 55.5+55.5+.5= 111.5

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