Answer / anjum kabir

A + B + C | 9 + 3 + 1 = 13 = 6 + 5 + 2
C + D + E | 1 + 8 + 4 = 13 = 2 + 7 + 4
E + F + G | 4 + 7 + 2 = 13 = 4 + 8 + 1
G + H + I | 2 + 5 + 6 = 13 = 1 + 3 + 9
Value of E = 4

13*4 = 52
1+2+3+....+9 = 45

Then C+D+E must be equal to 7
or they must from 1 , 2 or 4.

1 and 2 for E cannot satisfy as because 1 and 2 cannot
come together in C+D+E
hence 1 and 4 and 2 and 4 should be together.

so you get two solutions and putting them any of the either
way you get E = 4. and everynumber gets satisfied with a
unique value.

Answer / vyas

the values from 1-9 can be substed for a-i....
a=6,b=5,c=2,d=7,e=4,f=8,g=1,h=3,i=9

Answer / manikandan

the alphabets a to i can be replaced by numbers 1-9
a=9,b=3,c=1,d=8,E=4,f=7,g=2,h=6,i=5

Answer / rohit parimal

a+b+c=13 - eq 1

c+d+e=13 - eq 2

e+f+g=13 - eq 3

g+h+i=13 - eq 4

we will add all the equations

a+b+c+c+d+e+e+f+g+g+h+i=52 - eq 5

a+b+c+d+e+f+g+h+i+(c+e+g)=52

as the numbers are from 1 to 9
the addition of nine numners from 1 to 9 is 45.
so
a+b+c+d+e+f+g+h+i=45 -eq 6

Putting the value from eq 6 in eq 5

45+c+e+g=52 - eq 7

c+e+g=7 - eq 8

eq 2 says c+d+e=13

Subtracting eq 8 from eq 2

c+d+e-c-e-g=13-7

d-g=6 - eq 9

when we put value 4 in g then the value of d should be 10.
Objction.
So value of g is 1 or 2.

eq 3 says e+f+g=13

When we put the vaue of g as 1 then f should be 8 and e
should be 4.
When we put the value of g as 2 then f should be 9 and e
should be 2.Objection (because no two alphabets can be
same.)

Answer / g3

value of e cannot be found... data inadequate...

Answer / asp

a,b,c...e if rational no, infinite solutions possible

Answer / salma

c+d+e=13 or e+f+g=13

we can equally substitute the value of these

so...

e=13/3=4.3333333333333333333333333333333

Answer / sachin b. umbarkar

a+b+c=13
c+d+e=13
Thus, a+b+c=c+d+e
a+b=d+e .................(I)

e+f+g=13
g+h+i=13
Thus, g+h+i=e+f+g
h+i=e+g ...............(II)

Now add (I)and(II)
We get ,

a+b+h+i=d+g+2e
Thus,
e=(a+b+h+i-d-g)/2 .........Answer

Answer / kavitha

no unique solution but it can bnythng from 1-9

a=11
b=1
c=1
d=11
e=1
f=1
g=11
h=1
i=1
so at last e can be even 1

Answer / revathy

c=13-a-b
thus 13-a-b+d+e=13
e=a+b-d

This maynot have a unique solution
One such solution is:
if a=1, b=1, d=1
e=1
thus satisfying all the equations

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