Answer / kathiresan

#include<stdio.h>
#include<string.h>

int main()
{
char *str1 = "Hello";
char *str2 = "Hello";

int len1,len2;
len1 = strlen(str1);
len2 = strlen(str2);
if(len1 != len2)
{
printf("\nBoth Strings are not matched");
return 0;
}

while(*str1)
{
if(*str1 == *str2)
{
*str1++;
*str2++;
}
else
{
printf("\nString Not Matched\n");
return 0;
}
}
printf("\nBoth String are EQual");
}

main() { struct date; struct student { char name[30]; struct date dob; }stud; struct date { int day,month,year; }; scanf("%s%d%d%d", stud.rollno, &student.dob.day, &student.dob.month, &student.dob.year); }

1 Answers  

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main( ) { int a[2][3][2] = {{{2,4},{7,8},{3,4}},{{2,2},{2,3},{3,4}}}; printf(“%u %u %u %d \n”,a,*a,**a,***a); printf(“%u %u %u %d \n”,a+1,*a+1,**a+1,***a+1); }

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main() { show(); } void show() { printf("I'm the greatest"); }

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main() { int i=_l_abc(10); printf("%d\n",--i); } int _l_abc(int i) { return(i++); }

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#ifdef something int some=0; #endif main() { int thing = 0; printf("%d %d\n", some ,thing); }

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#include<stdio.h> main() { int i=1,j=2; switch(i) { case 1: printf("GOOD"); break; case j: printf("BAD"); break; } }

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main() { char *p; int *q; long *r; p=q=r=0; p++; q++; r++; printf("%p...%p...%p",p,q,r); }

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struct point { int x; int y; }; struct point origin,*pp; main() { pp=&origin; printf("origin is(%d%d)\n",(*pp).x,(*pp).y); printf("origin is (%d%d)\n",pp->x,pp->y); }

1 Answers  

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main ( ) { static char *s[ ] = {“black”, “white”, “yellow”, “violet”}; char **ptr[ ] = {s+3, s+2, s+1, s}, ***p; p = ptr; **++p; printf(“%s”,*--*++p + 3); }

1 Answers  

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main() { int c = 5; printf("%d", main||c); } a. 1 b. 5 c. 0 d. none of the above

2 Answers   HCL,

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main() { char name[10],s[12]; scanf(" \"%[^\"]\"",s); } How scanf will execute?

2 Answers  

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main() { int x=5; for(;x!=0;x--) { printf("x=%d\n", x--); } } a. 5, 4, 3, 2,1 b. 4, 3, 2, 1, 0 c. 5, 3, 1 d. none of the above

2 Answers   HCL,

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