#include<stdio.h>
int main()
{
int x=2,y;
y=++x*x++*++x;
printf("%d",y);
}
Output for this program is 64.
can you explain how this output is come??
#include<stdio.h> main() { char s[]={'a','b','c','\n','c','\0'}; char *p,*str,*str1; p=&s[3]; str=p; str1=s; printf("%d",++*p + ++*str1-32); }
plz tell me the solution.......... in c language program guess any one number from 1 to 50 and tell that number within 8 asking question in yes or no...............
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‎#define good bad main() { int good=1; int bad=0; printf ("good is:%d",good); }
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Is there any difference between the two declarations, 1. int foo(int *arr[]) and 2. int foo(int *arr[2])
Is it possible to type a name in command line without ant quotes?
main() { int i=300; char *ptr = &i; *++ptr=2; printf("%d",i); }
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/*what is the output for*/ void main() { int r; printf("Naveen"); r=printf(); getch(); }