Answer / gayathri sundar

#include<stdio.h>
#include<string.h>
main(int argc, char *argv[])
{
char *string = argv[1];
int len = strlen(string);
int i = 0;
int j = len - 1;
printf("string before is %s\n", string);
printf("len is %d\n", len);
while(i <= j)
{
*(string+i) += *(string+j);
*(string+j) = *(string+i) - *(string+j);
*(string+i) = *(string+i) - *(string+j);
i++;
j--;
if(len % 2)
if(i == j) break;
}
printf("reversed string is %s\n", string);
}

Answer / manish pathak

//********this is perfect answer***************

#include<stdio.h>
#include<conio.h>
void main()
{
int i,j,n,num,rem,l;
char s[]="abcde";
l=sizeof(s)-1;
for(i=0,j=l-1;i<=(l-1)/2;i++)//save space n/2
{

s[i]=s[i]+s[j-i];
s[j-i]=s[i]-s[j-i];
s[i]=s[i]-s[j-i];

}

s[l]='\0';
printf("%s",s);
getch();
}

Answer / a

It's all O(n). You're finding the length of the string,
which itself is an O(n) operation.
So, O(n + n/2) = O(n).

Answer / mm chen

#include <iostream>
#include <string>
using std::string;
using std::cout;
using std::endl;
using std::cin;

int main()
{
string s("abcdefghijklmnopqrstuvwxyz");
string::size_type s_size = s.size();

for (string::size_type x = 0; x != s_size; x++){

if ( (s_size -x -1) > x ){

s[x] ^= s[s_size - x -1];
s[s_size - x -1] ^= s[x];
s[x] ^= s[s_size - x -1];

}else{
break;
}

}

cout << s << endl;
}

Answer / anurag

int i=0,len=strlen(str);
int j=len/2;len--;
while(i<j)
{
*(str+i)^=*(str+len)^=*(str+i)^=*(str+len);
len--;i++;
}

Answer / atul kabra

#include<stdio.h>

void reverse(char *);

void main()
{
char str[]="Hello";

reverse(str);
printf("Reverse String is %s",str);

}

void reverse(char *p)
{

char *q=p;
while(*++q!='\0');
q--;

while(p<q)
{
*p=*p+*q;
*q=*p-*q;
*p=*p-*q;
p++;
q--;
}

}

Answer / suraj bhan gupta

#inclue<stdio.h>
#include<string.h>
main(){
char a[10],i;
int len=1;
printf(" Enter string ");
fgets(a,9,stdin);

len = strlen(a);


for(i=0 ; i<(len/2) ; i++){
a[i]=a[i]+a[len-2];
a[len-2]=a[i]-a[len-2];
a[i]=a[i]-a[len-2];
len--;
}
printf("\n Reverse string with n/2 complexity
%s",a);
return 0;
}

Answer / snehal

#inclue<stdio.h>
#include<string.h>
main(){
char a[10],i;
int len=1;
printf(" Enter string ");
fgets(a,9,stdin);

len = strlen(a);


for(i=0 ; i<=(len/2) ; i++){
a[i]=a[i]+a[len-1];
a[len-1]=a[i]-a[len-1];
a[i]=a[i]-a[len-1];
len--;
}
printf("\n Reverse string with n/2 complexity
%s",a);
return 0;
}

Answer / raghuram

#include<iostream.h>

#include<string.h>//complexity-n/2

int main()
{
int i,l,l1;
char str[100];
cout<<"enter string:";
gets(str);
l=strlen(str);
if(l%2==0)
l1=(l/2-1);
else
l1=l/2;
for(i=0;i<=l1;i++)/*swap elements from 2 ends till u reach
middle part of array*/
{
char t=str[i];
str[i]=str[l-i-1];
str[l-i-1]=t;
}
str[l]=0;
cout<<"\n\nreversed string is:"<<str;
getch();
return 0;
}

Answer / prof.muthu (9962940220)

refer c book!
or
contact me

prog. to produce 1 2 3 4 5 6 7 8 9 10

4 Answers   TCS,

Write a C program to print look and say sequence? For example if u get the input as 1 then the sequence is 11 21 1211 111221 312211 12112221 .......(it counts the no. of 1s,2s etc which is in successive order) and this sequence is used in run-length encoding.

1 Answers  

Ramesh’s basic salary is input through the keyboard. His dearness allowance is 40% of basic salary, and house rent allowance is 20% of basic salary. Write a program to calculate his gross salary.

1 Answers  

main() { int i=0; for(;i++;printf("%d",i)) ; printf("%d",i); }

1 Answers   Zoho,

main() { char i=0; for(;i>=0;i++) ; printf("%d\n",i); }

2 Answers  

What is the hidden bug with the following statement? assert(val++ != 0);

1 Answers  

There is a lucky draw held every day. if there is a winning number eg 1876,then all possible numbers like 1867,1687,1768 etc are the numbers that match irrespective of the position of the digit. Thus all these numbers qualify fr the lucky draw prize Assume there is no zero digit in any numbers. write a program to show all the possible winning numbers if a "winning number"is passed as an arguments to the function.

1 Answers   Nagarro,

which function is used to clear the buffer stream on gcc? for example: I wrote following code on gcc #include<stdio.h> int main(void) { char ch; int a,b; printf("\nenter two numbers:\t"); scanf("%d%d",&a,&b); printf("enter number is %d and %d",a,b); printf("\nentercharacter:\t"); scanf("%c",&ch); printf("enter character is %c",ch); return 0; } in above progarm ch could not be scan. why?plz tell me solution.

2 Answers  

main() { int i=_l_abc(10); printf("%d\n",--i); } int _l_abc(int i) { return(i++); }

2 Answers  

How can you relate the function with the structure? Explain with an appropriate example.

0 Answers  

String copy logic in one line.

11 Answers   Microsoft, NetApp,

x=2 y=3 z=2 x++ + y++; printf("%d%d" x,y);

2 Answers