Is the following statement a declaration/definition. Find
what does it mean?
int (*x)[10];
Answer / susie
Answer :
Definition.
x is a pointer to array of(size 10) integers.
Apply clock-wise rule to find the meaning of this definition.
| Is This Answer Correct ? | 3 Yes | 1 No |
union u { union u { int i; int j; }a[10]; int b[10]; }u; main() { printf("\n%d", sizeof(u)); printf(" %d", sizeof(u.a)); // printf("%d", sizeof(u.a[4].i)); } a. 4, 4, 4 b. 40, 4, 4 c. 1, 100, 1 d. 40 400 4
main() { int a=10,*j; void *k; j=k=&a; j++; k++; printf("\n %u %u ",j,k); }
#include<conio.h> main() { int x,y=2,z,a; if(x=y%2) z=2; a=2; printf("%d %d ",z,x); }
main() { int i, n; char *x = “girl”; n = strlen(x); *x = x[n]; for(i=0; i<n; ++i) { printf(“%s\n”,x); x++; } }
main() { int (*functable[2])(char *format, ...) ={printf, scanf}; int i = 100; (*functable[0])("%d", i); (*functable[1])("%d", i); (*functable[1])("%d", i); (*functable[0])("%d", &i); } a. 100, Runtime error. b. 100, Random number, Random number, Random number. c. Compile error d. 100, Random number
How to count a sum, when the numbers are read from stdin and stored into a structure?
¦void main() ¦{ ¦int i=10,j; ¦ j=i+++i+++i; ¦printf("%d",j); ¦getch(); ¦} ¦ output:-30 but in same question if we write as- ¦void main() ¦{ ¦int i=10; ¦ int j=i+++i+++i; ¦printf("%d",j); ¦getch(); ¦} ¦ output:-33 why output is changed from 30 to 33. Can any body answer...
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