Write a program that reads a dynamic array of 40
integers and displays only even integers
Answers were Sorted based on User's Feedback
Answer / guest
logic is:
for(i=0;i<40;i++)
{
if(a[i]%2==0)
{
printf("%d",a[i]);
}
}
Is This Answer Correct ? | 3 Yes | 1 No |
Answer / mohammedayub.y(c.i.e.t)
#include<stdio.h>
#include<conio.h>
void main()
{
int Array[40],i;
printf("Enter the array elements one by one:\n");
for(i=0;i<40;i++)
{
scanf("%d",&Array[i]);
}
printf("The even integers are:\n");
for(i=0;i<40;i++)
{
if(Array[i]%2==0) printf("%d\n",Array[i]);
}
getch();
}
Is This Answer Correct ? | 2 Yes | 1 No |
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