Answer / guest

logic is:


for(i=0;i<40;i++)
{
if(a[i]%2==0)

{
printf("%d",a[i]);
}

}

Answer / mohammedayub.y(c.i.e.t)

#include<stdio.h>
#include<conio.h>
void main()
{
int Array[40],i;
printf("Enter the array elements one by one:\n");
for(i=0;i<40;i++)
{
scanf("%d",&Array[i]);
}
printf("The even integers are:\n");
for(i=0;i<40;i++)
{
if(Array[i]%2==0) printf("%d\n",Array[i]);
}
getch();
}

Is the following code legal? typedef struct a { int x; aType *b; }aType

1 Answers  

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void func1(int (*a)[10]) { printf("Ok it works"); } void func2(int a[][10]) { printf("Will this work?"); } main() { int a[10][10]; func1(a); func2(a); } a. Ok it works b. Will this work? c. Ok it worksWill this work? d. None of the above

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How to access command-line arguments?

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Code for 1>"ascii to string" 2>"string to ascii"

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#include<stdio.h> main() { char s[]={'a','b','c','\n','c','\0'}; char *p,*str,*str1; p=&s[3]; str=p; str1=s; printf("%d",++*p + ++*str1-32); }

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#define SQR(x) x * x main() { printf("%d", 225/SQR(15)); } a. 1 b. 225 c. 15 d. none of the above

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plz send me all data structure related programs

2 Answers  

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Write a program that reads a dynamic array of 40 integers and displays only even integers

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Is it possible to print a name without using commas, double quotes,semi-colons?

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main() { extern i; printf("%d\n",i); { int i=20; printf("%d\n",i); } }

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