What are the components of the workflow manager?
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How can we store previous session logs?
design of staging area?
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what are presession,postsession success and postsession failure commands ?
Have you worked with/created Parameter file
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what is casual dimension?
To provide support for Mainframes source data,which files r used as a COBOL files
generate Unique sequence numbers for each partition in session with Unconnected Lookup ? Hi All, Please help me to resolve the below issue while Applying partitioning concept to my Session. This is a very simple mapping with Source, Lookup , router, and target. I need to Lookup on the target and compare with the source data, if any piece of data is new then Insert, and If any thing change in the existed data then Update. while Inserting the new records to the target table I'm generating sequence numbers with Unconnected lookup, by calling the maximum PK ID from the target table. The above flow is working fine from last one year. Now I wish to apply the Partitioning concept to the above floe(session) At source I used 4 pass through partitions.(For Each partition different filter conditions to pull the data from source) at Target I used 4 passthrough Partitions. it is working fine for some data, but for some rows for Insert Operation , it is throwing Unique key errors, because while Inserting the data it is generating the same sequence key twice. In detail : 1st row is coming from 1st partition and generated the sequence number 1 for that row. 2nd row is coming from 1st partition and generated the sequence number 2 for that row 3rd row is coming from the 2nd partition generated the sequence number 2 again for that row. (it must generate 3 for this row) the issue is becuase of generating the same sequence numbers twice for different partitions. Can any one Please help me to resolve this issue. While Applying partitions how can I generate a Unique Sequence numbers from Unconnected lookup for Each partitioned data. Regrads, N Kiran.
What is diff between connected and unconnected lookup?
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