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US Technology Placement Paper 19 Feb 2007 - Kerala

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US Technology Placement Paper 19 Feb 2007 - Kerala..

Answer / geroge

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I attended the campus interview conducted in my coll. for US Tech. This
time they had changed the pattern of questioning. Usually there are 32
ques in the first part but this time there were only 18.

first section conatined 18 ques based on analytical reasoning. Then the
next section 19-57 was the comprehension passage and some verbal
reasoning. There were 5 passages .

The last section consisted of logical reasoning (58-90). the test was for
90 min.

The results for aptitude were given by 1:30. gd was ok they looked if u
wre confident in the points u were bringing in,make sure an argument does
not break ,it will be good if u conclude. Be an active member in the gd .


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some of the gd topics

1.black or white
2.bollywood or mollywood
3.should Abdul Kalam continue as president
4.should the captial be shifted from tvm to cochin
5.dress code
6.ragging
7.should trade unions b there in it copmanies
8.use of mobile phones

From a group of 8 they selected min of 4 and a max of 6. gd was over by
4:30pm.


my interview was around 8pm. Some had just HR and some had deep technical
questions. I had tech ques and HR. but the atmosphere was cool . Technical
questions are asking from c and c++ mostly.

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US Technology Placement Paper 19 Feb 2007 - Kerala..

Answer / malay verma

need Question paper immediately, Pls Send Me ASAP

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SNAPDEAL QUESTIONS 1. A train is going at a speed of 60kmph towards Delhi and returned back at a speed of 30kmph. What is its average speed? ANS : (2*30*60)/(30+60) = 40kmph 2. How many different 4 letter words can be framed that have at least one vowel? ANS : 264 - 214 (total no of 4 digits words – no of words with no vowels) 3. Write an algorithm to find out a number from an array of numbers where only one number occurs once and rest all occurs twice. ANS : XOR all the numbers ,you will get the number with single occurrences . 4. Which among the following have the product of the distance between opposite sides of a regular polygon and it side equals one fourth of the area. A. hexagon B. octagon C. n=16 D. n=18 ANS : n=16.(area of regular polygon = apothem*perimeter/2 Apothem = distance between opposite sides/2 Area = (opp_side_dist * n * a )/4 Product of opp_side_dist and side of reg. polygon = opp_side_dist * a For n= 16 the ration becomes 1:4 5. Which of the following cannot be a relation between two variables? ANS = 4th diagram. 6.what will be the output of this program Void print (int n) { If (n>0) { printf(“hello”); print(n-1); } printf(“world”); } ANS : N times hello followed by N+1 times world. 7. Which among the following cannot be used for future prediction? ANS : 4th Diagram. 8. There are 25 horses. We have to find out the fastest 3 horses In one race maximum 5 horses can run. How many such races are required in minimum to get the result. ANS : 7 races (A. first run all horses = 5 races, eliminate 4th 5th of all races. B. Run horses who came 1st in those 5 races = 1 race , the horse coming first is the fastest Run horses a. 2nd and 3rd with the fastest horse (in first time race A) b. 2nd and 3rd coming horse in B. c. The horse who came 2nd with the horse(who came 2nd in race B) in race A You will have the fastest 3 horses.) 9. In a game of rolling dice you are given 2 dice and you have to roll them. Whatever is the outcome the player will win that many dollars. What should the game owner charge each player (optimum) so that he doesn’t have to bear any loss? ANS : $7 10. We have a function REV(“string”,m,n).This function is capable of reversing the caharacters in the string from mth location to nth location. e.g. REV(“abcd”,2,3) &#61672; the output will be acbd We need to swap a string from a position,e.g. SWAP(“abcdefg”,4) &#61672; output needs to be efgabcd. How can the REV function used do this. ANS : L = string length,N= position given in SWAP function. SWAP(“abcdefg”,4) = REV(REV(REV(“abcdefg”,N+1,L),1,N),1,L).

1 Answers   SnapDeal,


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