Answer / raj kumar

I took up Infosys test on 27th of feb. Getting placed in Infosys is not
that easy and not that difficult. The written part consists of two
sections.

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REASONING (30 ques in 40 mins)

VERBAL (40 ques in 35 min)

REASONING:

you have to be definitely study these topics even if u leav others

1) puzzle test (quite easy)
2) figure series (easy)
3) data sufficiency (important)
4) data interpretation
5) logical reasoning i.e. syllogism( easy)
6) blood relations

These are the important topics. give more stress on them.

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for all these topics refer Non-verbal and Reasoning -- R.s Agarwal.

Verbal:


1) 2 reading comprehensions, one very very lengtht, have it as last option.

2) one statement will be given and some part will be underlined and 4
options were given. u have to correct that sentence from the options which
best suits.

3)some small passage will be given and you have to infer something 4m .

4)synonyms, antonyms.

If you clear this, you will be called for HR.

This round merely tests YOUR Communication Skills, how u interact. talk
loudly, boldly, clearly.

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Interview Questions:

1) were u confident of clearing 1st round?
2) did u prepare 4 infy test?
3) what books did you refer?
4) strengths and how does it suit u, just give examples(if u say positive
attitude as strength, give an example for it)
5)what songs u like?
6)other strenghts?
7)How do you relate it to you?
8)suppose if you rejected this time how will u react?
9)hobbies?
10)ready to go abroad?
11)they gave some puzzle to solve. They dont mind about its solution. They
just see how you Approach to it.

12)any questions from your side?

So these were the questions asked 4 me.

well, have self confidence, dont get tensed, be cool and have a smiling
face while you interact with HR.

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Answer / ashutosh kumar

i need a latest infosys placement paper.

SNAPDEAL QUESTIONS 1. A train is going at a speed of 60kmph towards Delhi and returned back at a speed of 30kmph. What is its average speed? ANS : (2*30*60)/(30+60) = 40kmph 2. How many different 4 letter words can be framed that have at least one vowel? ANS : 264 - 214 (total no of 4 digits words – no of words with no vowels) 3. Write an algorithm to find out a number from an array of numbers where only one number occurs once and rest all occurs twice. ANS : XOR all the numbers ,you will get the number with single occurrences . 4. Which among the following have the product of the distance between opposite sides of a regular polygon and it side equals one fourth of the area. A. hexagon B. octagon C. n=16 D. n=18 ANS : n=16.(area of regular polygon = apothem*perimeter/2 Apothem = distance between opposite sides/2 Area = (opp_side_dist * n * a )/4 Product of opp_side_dist and side of reg. polygon = opp_side_dist * a For n= 16 the ration becomes 1:4 5. Which of the following cannot be a relation between two variables? ANS = 4th diagram. 6.what will be the output of this program Void print (int n) { If (n>0) { printf(“hello”); print(n-1); } printf(“world”); } ANS : N times hello followed by N+1 times world. 7. Which among the following cannot be used for future prediction? ANS : 4th Diagram. 8. There are 25 horses. We have to find out the fastest 3 horses In one race maximum 5 horses can run. How many such races are required in minimum to get the result. ANS : 7 races (A. first run all horses = 5 races, eliminate 4th 5th of all races. B. Run horses who came 1st in those 5 races = 1 race , the horse coming first is the fastest Run horses a. 2nd and 3rd with the fastest horse (in first time race A) b. 2nd and 3rd coming horse in B. c. The horse who came 2nd with the horse(who came 2nd in race B) in race A You will have the fastest 3 horses.) 9. In a game of rolling dice you are given 2 dice and you have to roll them. Whatever is the outcome the player will win that many dollars. What should the game owner charge each player (optimum) so that he doesn’t have to bear any loss? ANS : $7 10. We have a function REV(“string”,m,n).This function is capable of reversing the caharacters in the string from mth location to nth location. e.g. REV(“abcd”,2,3)  the output will be acbd We need to swap a string from a position,e.g. SWAP(“abcdefg”,4)  output needs to be efgabcd. How can the REV function used do this. ANS : L = string length,N= position given in SWAP function. SWAP(“abcdefg”,4) = REV(REV(REV(“abcdefg”,N+1,L),1,N),1,L).

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