Answer / Prakasha M

Selecting a suitable circuit breaker for an induction motor involves considering various factors such as voltage, current, short-circuit capacity, and power factor. To size the circuit breaker for a 100 kW, 415V, 0.85 power factor motor with 0.95 efficiency, follow these steps:
1. Calculate the active (real) power P = 100 kW.
2. Determine the apparent power S based on the power factor: S = P / Power Factor = 100 kW / 0.85 = 117.64 kVA.
3. Calculate the rated current I = S / (Voltage x Efficiency) = 117.64 kVA / (415 V x 0.95) = 281.4 A.
4. Choose a circuit breaker with a rating that can handle this current and meet the short-circuit capacity requirements for your specific application.

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