Answer / anju

if directory block is given as 0 then it is not a pds and
ps doesn't have members .

Answer / deenval

yes min no of member should be zero, but max no. will be 5.
according to formula m = 6*n - 1, when n=1 then m will be 5
and when n will be to 2 then m will be 11.

Answer / santosh

correct answear is Zero, Six is the Max no.

Answer / steve holton

Add'l info to above - I was wondering where the 6n-1 stuff
came from, and found that ISPF adds 30 bytes of user
information to each entry, so the total for each entry is 42
bytes. So for an ISPF directory block (assuming you do NOT
use STATS OFF...) 6 entries will fir in each directory
block. The LAST entry in the directory is always a "dummy"
entry with member name x'FFFFFFFFFFFFFFFF', so I am assuming
that the 6n-1 is actually a calculation as to how many
members a directory of a certain size can hold. So, for
example, an ISPF (STATS ON) dataset can hold (6 x number of
directory blocks) - 1 (for the x'FF... dummy entry) members,
asuming that you don't x37 abend because "data size".

Note that the binder (linkage editor) apppears to fit 7
members per directory block (24 bytes user data = 36
bytes/entry), so for load modules (not PDSE program
objects...), the corresponding formula is 7n - 1, and for
IEBCOPY or IEBUPDTE created members with no user data (12
bytes per entry) 21n - 1.

Answer / steve holton

PDS directory blocks are 256 bytes long. The first halfword
(2 bytes) are used to indicate the number of bytes used in
the block, leaving 254 bytes for directory entries.

Directory entries are variable in size, and are each at
least 12 bytes long, and up to 74 bytes long (12 byte "base"
length plus up to 62 bytes user data).

Directory blocks may have no members, so 0 is the minimum
possible members in a block. If the question is re-worded to
something like "what is the minimum number of entries in a
FULL directory block?", the answer is floor(254/74) = 3.
That is, every PDS directory block is capable of holding AT
LEAST 3 entries.

Maximum possible entries in a full directory block would be
floor(254/12) = 21.

Answer / janar singh

calculatin by using the farmoula m=6*n-1, where n = no of db, so if n=1 then max mem will be 5. if i m wrong correct me pls.

Answer / karthik

i have doubt in will anyone rectify it 6n-1
what is that 1 indicates

Answer / shailendra

i agree with ans of santosh

their is formula to count for max no.member

m = (6*n)-1 (but this formula implement when n directory
block is greater then one otherwise when n =1 so m will 6)

Answer / guest

SIX

Answer / anisha

Thats not pretty clear, if using the formula minimum number
is zero, maximum should be:
(6*0)-1 = -1

So, the munimum possible is 1, and the maximum possible is
5.

Why we us SYSTSIN DD with IKJEFT01 (TSO Utility) to execute a COBOL DB2 program? Why can't we use SYSIN DD?  

1 Answers   TCS,

I have 2 steps in my exec statement , in first step I am creating a gdg, and the output of this step is going into second step as a input, and this second step is abended , now how could i approach in this case.

5 Answers   Bank Of America,

What is maximum length of block size?

5 Answers   Cap Gemini, Kanbay, TCS,

what disp parameter we mention for creation of temporary dataset so that we can use it in later steps?

0 Answers   IBM,

Brief description of inline procedure of jcl.

0 Answers  

What are SD37, SB37, SE37 abends?

4 Answers  

What is the purpose of disp parameter?

0 Answers  

i have a jcl in which 4 & 5 step creates a new generation. 4th step output is as input for the 6th step & 5th step output is used as input in the 7th step. How they are refered as in the 6th & 7th steps? If the job abends in 6th step then how the 5th step output is refered in 7th step?

6 Answers   IBM,

Hi, Please clear me when COND=ONLY and COND=EVEN. Explain me with example.

2 Answers   GJ,

Name the system library from which modules are retrieved at execution

2 Answers  

How to use COND Parameter in jcl

4 Answers   NIIT, Wipro,

Explain dd statement in jcl?

0 Answers