Answer / kang chuen tat (malaysia - pen

Answer 75 - (i) Number average molecular weight = Ma Xa + Mb Xb + Mc Xc = 14 x 0.5 + 16 x 0.3 + 18 x 0.2 = 15.4 kg / mol. (ii) Weight average molecular weight = (Ma Xa Ma + Mb Xb Mb + Mc Xc Mc) / (Ma Xa + Mb Xb + Mc Xc) = (14 x 0.5 x 14 + 16 x 0.3 x 16 + 18 x 0.2 x 18) / 15.4 = 15.558 kg / mol. (iii) Polydispersity = [ answer in (ii) ] / [ answer in (i) ] = 15.558 / 15.4 = 1.0103. (iv) Degree of polymerization = (Ma Xa + Mb Xb + Mc Xc) / (molecular weight of repeat unit) = (15.4 kg / mol) / (12 g / mol) = 1.283 k = 1283. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.

can anyone send me the written test paper of Indian oil corporation ltd. My email id is pratuljakhmola@yahoo.com

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hello everyone do anyone have interview questions for any chemical industry please email me at ravijallu.nitj@gmail.com

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Which part of oil creates smoke? ( aliphatic, aromatic, paraffin)

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Explain how can one estimate how the friction factor changes in heat exchanger tubes with a change in temperature?

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