There are 100 lines in a file. How to print line number 31-50 and 81-90 in unix with a single command.
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Answer / xx
awk '(NR>31 && NR<50) || (NR>81 && NR <90) filename.txt
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if i have records like these (source table) rowid name 10001 gdgfj 10002 dkdfh 10003 fjfgdhgjk 10001 gfhgdgh 10002 hjkdghkfh the target table should be like these by using expression tranformation. (Target table) rowid name 10001 gdgfj 10002 dkdfh 10003 fjfgdhgjk xx001 gfhgdgh xx002 hjkdghkfh (that means duplicated records should contain XX in there rowid)
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hi all my source looking like below column1 column2 101,102,103 abc,def,ghi 1001,1002,1003 a,b,c i want my target is column1 column1 101 abc 102 def 103 ghi 1001 a 1002 b 1003 c any one can you help
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