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How would you code a merge that will write the matches of
both to one data set, the non-matches from the left-most
data set to a second data set, and the non-matches of the
right-most data set to a third data set?
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Answer / sas job searcher
data x1y1
x1y0
x0y1;
/* x1y1, x1y0, x0y1 are output data set names */
merge left_most(in=x) right_most(in=y);
by id;
/* write all matches to x1y1: */
if x=1 and y=1 then output x1y1;
/* non-matches from the left-most data set: */
if x=1 and y=0 then output x1y0;
/* non-matches from the right-most data set: */
if x=0 and y=1 then output x0y1;
run;
| Is This Answer Correct ? | 11 Yes | 1 No |
Answer / reddy
data both left_only right_only;
merge dataset1(in=a) dataset2(in=b);
by variable;
if a and b then output both;
if a and not b then output left_only;
if b and not a then output right_only;
run;
i think these is the easy way of writing the code,if any
one nows other please specify.thanks!
| Is This Answer Correct ? | 11 Yes | 4 No |
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How would you code a merge that will write the matches of both to one data set, the non-matches from the left-most data set to a second data set, and the non-matches of the right-most data set to a third data set.
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