A current of 2A flows for 10 hour through a 100 ohm resistor. The energy consumed by the resistor is:(a) 0.5 kWh(b) 4 kWh(c) 2 kWh(d) 0.02 kWh
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Answer / jashobanta kisan
Answer by Jashobanta
P= i2rt
P=2^2.100.10
=4000wh
=4kwh
| Is This Answer Correct ? | 4 Yes | 2 No |
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