what is vacuum....?
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Answer / sumit singhania
vaccum is pressure below atmospheric pressure
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Answer / mukul kumar dohare
Vacuum is the negative pressure aggest below of ATM pressure ..
1atm=760mmhg
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ENGINEERING MATERIAL - EXAMPLE 12.3 : Let a ^ 2 = a x a and a ^ 3 = a x a x a where ^ is power function. Niobium is a metal with a body-centered cubic structure. The length of the unit cell structure is b = 0.3349 nm. (a) Find the volume for a unit cell structure for niobium. (b) There are 2 atoms per unit cell structure of niobium. The metal has a molar mass of 92.9 g / mol. One mole of the metal consists of 6.02 x 10 ^ 23 atoms. Find the mass of niobium per unit cell and the density of niobium.
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2 Answers MPCL, NFIL, Reliance, UPL,
ACCOUNTING AND FINANCIAL ENGINEERING - EXAMPLE 34.1 : (i) In the pricing of engineering bonds, 3 sets of data for Portfolio Value, Probability, Senior Tranche and Junior Tranche are : $2000, 81 %, $1000, $1000; $1000, 18 %, $1000, $0; $0, 1 %, $0, $0. By assuming independent defaults, find the price for : (a) Senior Tranche; (b) Junior Tranche. (ii) Assuming statistical independence of the values in the sample, the standard deviation of the mean (S) is related to the standard deviation of the distribution (s) by : N x S x S = s x s, where N is the number of observations in the sample used to estimate the mean. In a drug development project, let s = 1. Find the value of S if such a similar project is performed 100 times.
ENGINEERING DRAWING - EXAMPLE 18.2 : For a Vernier scale that consists of 0.11 cm per section, estimate the length on actual standard ruler of 0.1 cm per section for 2.39 m and 0.91 m.
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Question 42 - According to Margules Equation, P = x(1) p(1) g(1) + x(2) p(2) g(2) for a two-component mixture where P is bubble pressure, x is mole fraction, p is saturation pressure, g is constant given by ln g(1) = x(2) A x(2). Find the value of A as a constant when P = 1.08 bar, p(1) = 0.82 bar, p(2) = 1.93 bar in a 50 : 50 mole fraction mixture. Estimate the pressure required to completely liquefy the 30 : 70 mixture using the same equation, by proving P = 1.39 bar. Take note that ln g(2) = x(1) A x(1), ln g(1) = x(2) A x(2).
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QUANTUM CHEMISTRY AND CHEMICAL ENGINEERING - EXAMPLE 31.5 : In a wavefunction, let P(x) = A cos kx + B sin kx. By using the boundary conditions of x = 0 and x = l, where P(0) = P(l) = 0, prove by mathematical calculation that P(x) = B sin (npx / l) where p = 22 / 7 approximately, n is a rounded number. A, B and k are constants.
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