how can we generate row values like
1
1
1
2
2
2
3
3
3
using col generator
plz let me know
Answers were Sorted based on User's Feedback
Answer / koti
seq -----------cg------------seq
Take input file like
1
2
3
4
5
6
7
8
9
10
comming to CG
Column Method =Explicit
column Generate = Test
go to cg Porperties output ----Mapping----- map the test column----ok
next ,column---edit column meta data--columnname test--sqltype integer----parallel properties---genartor-
type=cycle,increment =1,intial vlue=1.
go to target file do link sort to outputfile
go to apt_config file
check how many node is their
if it 2 nodes
you just create one more node that means total 3nodes.
while runing a job run on 3 nodes.
you will get output like
1
1
1
2
2
2
3
3
3
4
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Answer / peeyush sehgal
Take input file like 0 1 2 3 4 5 6 7 8 9
seq -> trans -> seq
in transformer, clear its partitioning and sort the data.
then in stage variable
initialize sv=1
if inputlink%3=0 then sv+1 else sv
populate sv in output column.
| Is This Answer Correct ? | 0 Yes | 0 No |
hi All, i have one scenario like if source--->transformer-->2 target sequential files the 1 st target sequential file is loads the data from source and 2nd target sequntial file contain the 1st target total record count,and file name of 1 st target seq file and timestamp seperated by delimeter for example if source have 10 record the 1st target seq file hav 10 records and 2nd target seq file example 10|xyz.txt|20101110 00:00:00 could you please help me out how can i implement in datastage job.
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