Answer / rakesh

some functions allow to pass any number of arguments such as
printf ,scanf etc.

Answer / pavan mustyala

Check out the below link!!! it gives a nice insight of this
concept.

http://www.cprogramming.com/tutorial/c/lesson17.html

Anyways, this is about a function accepting variable number
of arguments i.e., at different places of calling that
function, number of arguments can differ.

Example:
int Some_func( int param1, ... ); is the declaration to it.

the 3 dots (called ellipsis) tells the compiller that it
accepts variable number of arguments.

main() { int i=0; for(;i++;printf("%d",i)) ; printf("%d",i); }

1 Answers   Zoho,

---

const int perplexed = 2; #define perplexed 3 main() { #ifdef perplexed #undef perplexed #define perplexed 4 #endif printf("%d",perplexed); } a. 0 b. 2 c. 4 d. none of the above

1 Answers   emc2, HCL,

---

How can u say that a given point is in a triangle? 1. with the co-ordinates of the 3 vertices specified. 2. with only the co-ordinates of the top vertex given.

1 Answers  

---

main() { int c = 5; printf("%d", main||c); } a. 1 b. 5 c. 0 d. none of the above

2 Answers   HCL,

---

main() { int i=10; void pascal f(int,int,int); f(i++,i++,i++); printf(" %d",i); } void pascal f(integer :i,integer:j,integer :k) { write(i,j,k); }

1 Answers  

---

---

#include <stdio.h> int main(void) { int a=4, b=2; a=b<<a+b>>2 ; printf("%d",a); return 0; }

0 Answers   Student,

---

There were 10 records stored in “somefile.dat” but the following program printed 11 names. What went wrong? void main() { struct student { char name[30], rollno[6]; }stud; FILE *fp = fopen(“somefile.dat”,”r”); while(!feof(fp)) { fread(&stud, sizeof(stud), 1 , fp); puts(stud.name); } }

1 Answers  

---

main() { signed int bit=512, i=5; for(;i;i--) { printf("%d\n", bit = (bit >> (i - (i -1)))); } } a. 512, 256, 128, 64, 32 b. 256, 128, 64, 32, 16 c. 128, 64, 32, 16, 8 d. 64, 32, 16, 8, 4

2 Answers   HCL,

---

Write a routine to draw a circle (x ** 2 + y ** 2 = r ** 2) without making use of any floating point computations at all.

2 Answers   Mentor Graphics, Microsoft,

---

main() { printf("%d", out); } int out=100;

3 Answers  

---

main() { int y; scanf("%d",&y); // input given is 2000 if( (y%4==0 && y%100 != 0) || y%100 == 0 ) printf("%d is a leap year"); else printf("%d is not a leap year"); }

1 Answers  

---

main() { int x=5; for(;x!=0;x--) { printf("x=%d\n", x--); } } a. 5, 4, 3, 2,1 b. 4, 3, 2, 1, 0 c. 5, 3, 1 d. none of the above

2 Answers   HCL,

---