Answer / amit kumar kunwar

as i is pointing to the address 400 and getting assigned a value of 0. this code is working perfectly. hence the Output is 0 for this code.

Answer / susie

Answer :

Undefined behavior

Explanation:

The second statement results in undefined behavior because
it points to some location whose value may not be available
for modification. This type of pointer in which the
non-availability of the implementation of the referenced
location is known as 'incomplete type'.

Write a program that produces these three columns sequence nos. using loop statement Sequence nos. Squared Squared + 5 1 1 6 2 4 9 3 9 14 4 16 21 5 25 30

1 Answers   GoDB,

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All the combinations of prime numbers whose sum gives 32

1 Answers   HHH,

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#include<stdio.h> void fun(int); int main() { int a; a=3; fun(a); printf("\n"); return 0; } void fun(int i) { if(n>0) { fun(--n); printf("%d",n); fun(--n); } } the answer is 0 1 2 0..someone explain how the code is executed..?

1 Answers   Wipro,

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main() { extern int i; i=20; printf("%d",i); }

1 Answers   Value Labs,

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#define FALSE -1 #define TRUE 1 #define NULL 0 main() { if(NULL) puts("NULL"); else if(FALSE) puts("TRUE"); else puts("FALSE"); }

1 Answers  

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which function is used to clear the buffer stream on gcc? for example: I wrote following code on gcc #include<stdio.h> int main(void) { char ch; int a,b; printf("\nenter two numbers:\t"); scanf("%d%d",&a,&b); printf("enter number is %d and %d",a,b); printf("\nentercharacter:\t"); scanf("%c",&ch); printf("enter character is %c",ch); return 0; } in above progarm ch could not be scan. why?plz tell me solution.

2 Answers  

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main() { char name[10],s[12]; scanf(" \"%[^\"]\"",s); } How scanf will execute?

2 Answers  

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prog. to produce 1 2 3 4 5 6 7 8 9 10

4 Answers   TCS,

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How do you create a really large matrix (i.e. 3500x3500) in C without having the program crash? I can only reach up to 2500. It must have something to do with lack of memory. Please help!

1 Answers  

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What is full form of PEPSI

0 Answers  

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Which one is taking more time and why ? :/home/amaresh/Testing# cat time.c //#include <stdio.h> #define EOF -1 int main() { register int c; while ((c = getchar()) != EOF) { putchar(c); } return 0; } ------------------- WIth stdio.h:- :/home/amaresh/Testing# time ./time_header hi hi hru? hru? real 0 m4.202s user 0 m0.000s sys 0 m0.004s ------------------ Witout stdio.h and with #define EOF -1 =================== /home/amaresh/Testing# time ./time_EOF hi hi hru? hru? real 0 m4.805s user 0 m0.004s sys 0 m0.004s -- From above two case , why 2nd case is taking more time ?

0 Answers  

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what will be the position of the file marker? a: fseek(ptr,0,SEEK_SET); b: fseek(ptr,0,SEEK_CUR);

2 Answers  

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