Answer / susie

Answer :

Compier error: Type mismatch in redeclaration of show.

Explanation:

When the compiler sees the function show it doesn't know
anything about it. So the default return type (ie, int) is
assumed. But when compiler sees the actual definition of
show mismatch occurs since it is declared as void. Hence the
error.

The solutions are as follows:

1. declare void show() in main() .

2. define show() before main().

3. declare extern void show() before the use of show().

Answer / ravneet kaur

ans: declaration terminated incorrectly.

Which one is taking more time and why ? :/home/amaresh/Testing# cat time.c //#include <stdio.h> #define EOF -1 int main() { register int c; while ((c = getchar()) != EOF) { putchar(c); } return 0; } ------------------- WIth stdio.h:- :/home/amaresh/Testing# time ./time_header hi hi hru? hru? real 0 m4.202s user 0 m0.000s sys 0 m0.004s ------------------ Witout stdio.h and with #define EOF -1 =================== /home/amaresh/Testing# time ./time_EOF hi hi hru? hru? real 0 m4.805s user 0 m0.004s sys 0 m0.004s -- From above two case , why 2nd case is taking more time ?

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