Give a very good method to count the number of ones in a 32
bit number.
(caution: looping through testing each bit is not a solution)




Answers were Sorted based on User's Feedback



Give a very good method to count the number of ones in a 32 bit number. (caution: looping through ..

Answer / raghuram

#include<iostream.h>
#include<conio.h>
/*no. of 1's in no. of 1's steps*/
int count(unsigned long int n)
{
int count=0;
while(n)
{
count++;
n=n&n-1;
}
return count ;
}

Is This Answer Correct ?    41 Yes 26 No

Give a very good method to count the number of ones in a 32 bit number. (caution: looping through ..

Answer / vijay

#include<stdio.h>
main()
{
int x=123,i=0;
while(x)
{
x=x&(x-1);
i++;
}
printf("Number of set bits are %d \n",i);
}

Is This Answer Correct ?    24 Yes 9 No

Give a very good method to count the number of ones in a 32 bit number. (caution: looping through ..

Answer / xyz

main()
{
int i=1177;
int j=0;
while(i>0)
{
if((i%2)!=0)
j++;
i=i/2;
}
printf("The number of one is %d\n", j);
}

Is This Answer Correct ?    12 Yes 6 No




Give a very good method to count the number of ones in a 32 bit number. (caution: looping through ..

Answer / lawrence

@Turk
your solution is O(n) not O(logn). your algorithm still
counts each zeros and ones.

Is This Answer Correct ?    2 Yes 1 No

Give a very good method to count the number of ones in a 32 bit number. (caution: looping through ..

Answer / sunny arora

/* This is a table which will contain number of ones
corrosponding to number value */
static int bits_in_char [256] ;

int bitcount (unsigned int n)
{
// works only for 32-bit ints

return bits_in_char [n & 0xffu]
+ bits_in_char [(n >> 8) & 0xffu]
+ bits_in_char [(n >> 16) & 0xffu]
+ bits_in_char [(n >> 24) & 0xffu] ;
}

Is This Answer Correct ?    9 Yes 9 No

Give a very good method to count the number of ones in a 32 bit number. (caution: looping through ..

Answer / turk

Here is an O(logn) solution

#include<stdio.h>

int numberOfOnesByte(unsigned char c, int length){
if (c==0)
return 0;
if (c==1)
return 1;
unsigned char left, right;
int lengthP = length/2;
left = c>>lengthP;
right = c-(left<<lengthP);
return numberOfOnesByte(left,length-lengthP)+numberOfOnesByte(right,lengthP);
}
int numberOfOnes(unsigned char *array, int start, int end, int length){
if(length==1){
return numberOfOnesByte(array[start],8);
} else {
int lengthP = length/2;
return numberOfOnes(array,start,start+lengthP-1,lengthP)+
numberOfOnes(array,start+lengthP,end,length-lengthP);
}
}
int main(){
unsigned char array[8] = {0xFF,0XAA,0xFF,0XAA,0xFF,0XAA,0xFF,0XAA};
printf("number of bits %d\n",numberOfOnes(array,0,7,8));
return 0;
}

Is This Answer Correct ?    3 Yes 5 No

Give a very good method to count the number of ones in a 32 bit number. (caution: looping through ..

Answer / pgmrsf

static void NumOfOnes(uint n)
{
int c = 0;
for (int i=0; i<10; i++)
{
if ((n & (int)Math.Pow(2, i)) == (int)Math.Pow(2,
i))
{
c++;
}
}
Console.WriteLine("{0}", c);
}

Is This Answer Correct ?    4 Yes 7 No

Post New Answer



More C Code Interview Questions

typedef struct error{int warning, error, exception;}error; main() { error g1; g1.error =1; printf("%d",g1.error); }

1 Answers  


How do you create a really large matrix (i.e. 3500x3500) in C without having the program crash? I can only reach up to 2500. It must have something to do with lack of memory. Please help!

1 Answers  


plz send me all data structure related programs

2 Answers  


main(){ int a= 0;int b = 20;char x =1;char y =10; if(a,b,x,y) printf("hello"); }

1 Answers   TCS,


#include<stdio.h> int main() { int x=2,y; y=++x*x++*++x; printf("%d",y); } Output for this program is 64. can you explain how this output is come??

1 Answers  






Write a program using one dimensional array to assign values and then display it on the screen. Use the formula a[i]=i*10 to assign value to an element.

1 Answers   Samar State University,


source code for delete data in array for c

1 Answers   TCS,


void main() { char ch; for(ch=0;ch<=127;ch++) printf(“%c %d \n“, ch, ch); }

1 Answers  


main() { char s[ ]="man"; int i; for(i=0;s[ i ];i++) printf("\n%c%c%c%c",s[ i ],*(s+i),*(i+s),i[s]); }

1 Answers   DCE,


main() { unsigned char i=0; for(;i>=0;i++) ; printf("%d\n",i); }

1 Answers  


main() { signed int bit=512, i=5; for(;i;i--) { printf("%d\n", bit >> (i - (i -1))); } } a. 512, 256, 0, 0, 0 b. 256, 256, 0, 0, 0 c. 512, 512, 512, 512, 512 d. 256, 256, 256, 256, 256

2 Answers   HCL,


main() { while (strcmp(“some”,”some\0”)) printf(“Strings are not equal\n”); }

1 Answers  






Categories