Answer / greenborhan

I actually don't know why we multiply by 25, but for
your better knowing we don't get the correct cut result
by multiplying mV by 25, this procedure is only true for
k-type thermocouple. But for all other types of
thermocouple you have to follow the specific table for mV
and temperature.
greenborhan@gmail.vcom

Answer / carl_ellis

Apparently, your temperature signal is linear across a mV
range, coming from some type of temperature transmitter,
and the mV value represents temperature/25.

If your source is a raw thermocouple signal, then
multiplying by 25 does NOT result in a true temperature
value because
- cold junction compensation has not be applied
- thermocouples are not linear

Temperature transmitters perform both of those tasks, cold
junction compensation and linearization of the output
signal.

Carl Ellis
Measure First

With N nodes and B branches what will have a network ???

0 Answers   BSNL,

---

What is the use instrument barriers? Can you give me review materials about this?

1 Answers  

---

what are the selections available in configuring a burnout protection of a controller? thanks

0 Answers   NPC Alliance Corporation,

---

What is open loop checking and close loop checking

1 Answers   BARC, NTPC,

---

how we calculate error in percentage when instrument calibrat

1 Answers  

---

What is Droop? What is Step/Gradient Limiter in Turbine Governor control?

0 Answers  

---

how commission a transmitter evev plant is already running

2 Answers  

---

what type problems create in radar level transmeter and what is its solution

2 Answers   Essar,

---

how to calibrate absolute pressure transmitter

7 Answers   ABB,

---

Capacitance, resistance ( colour coding ), parallel & series circuits.

0 Answers   CCIE,

---

how to install the Ph and Conductivity analyser? is there are any procedures which has to be maintained.

2 Answers  

---

why we cant transmit the dc current easily

1 Answers  

---