Answer / s pavan sudheer

copper losses vary with load. Copper loss is I^2 R loss, when we apply load aromatically the current will be increased so it is finalized that current drawing is directly proportional to copper losses.
   

If the load is 10Kw and power factor has to improve from 0.5 to 0.8,how can we select the capacitor rating accordingly.Illustrate by showing formula?

9 Answers  

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What is fault clearing time for Current Limiting Moulded Case Circuit Breaker?.

0 Answers   DAE, Hindalco,

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Which test will be more severe for VCB?

0 Answers   CPRI, Reliance,

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What is the difference between IGBT and TRIAC?

3 Answers  

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What is the diameter of electromagnetic field around a 11000/415v transformer ? Dose it affect people who live 3-4 meter beside it?

0 Answers  

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a)In a 3-phase 4-wire circuit, a circuit breaker is selected to protect the circuit whose highest fault level is 6.6 MVA. Determine the required minimum breaking capacity in kA. (Note: Covert 3-phase power in terms of kA to find answer.) b)Using the below, determine the required minimum making capacity in kA as a “peak value”. Rate breaking capacity (Icn) ka: Icn<= 1.5 Factor = 1.41 1.5

0 Answers  

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What is Traction? 1KVA Alternator, How much urrent taken?

0 Answers   Bhel,

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why the voltage is in digit of 11/33/132/220/440 please send me on shukrerabbi_abkhalil@rediffmail.com with thanks

3 Answers  

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v=I*R, i.e V is directly proportional to I. now P=V*I. so V=P/I. thus v is inversely proportional to I. so what is the correct one? If both are correct than for which kind of condition this 2 differ

3 Answers  

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800A 22KV TP OCB. explain

1 Answers  

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How shall i select the value of capacitor or inductor in a system?

0 Answers  

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what is current actully?significance of current...not rate of change of flow.....

3 Answers  

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