Answer / pardeep kumar

Suppose Area of slab is 99.00Sq ft = 9.20Sq.m
Suppose Dia 10mm at 125C/C Bothways r/f Provided,
For 1 Sq. m Area No Of Bars = 1/.125+1=9Nos
For bothways=18 nos single layer @ 1m each bar=18m

For Single layer in 1sqm=18mx0.62kg/mx9.20sqm=102.67kg
For double layer(top & bottom)-102.67x2=205.344kg

Answer / nilesh kulkarni

Suppose Area of slab is 99.00Sq ft = 9.20Sq.m
Suppose Dia 10mm at 125C/C Bothways r/f Provided,
For 1 Sq. m Area No Of Bars = 1/.125+1=9Nos
For boathways = 18Nos
Length Of 1Bar =1m,For 18 nos = 18 m
Now For 9.20 Sq. m Area = 18Nos x 18 r.mtr. = 324 R.mtrs.
So Unit Wt of 10mm Dia steel =0.62 Kg/m
So for 324 r. mtrs steel =324*0.62=201.5Kg Steel reqd of 10mm dia.

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