Answer / nagarajanselvaraj

#include<stdio.h>
void main()
{
int num,ocnum=1,foct=0,temp;
printf("\nEnter an integer = ");
scanf("%d",&num);
while(num>=8) //loop for converting decimal to octal
{
temp=num%8;
num=num/8;
ocnum=(ocnum*10)+temp;
}
ocnum=(ocnum*10)+num; //number is in reverse
while(ocnum!=1) //loop for reversing the octal result
{
temp=ocnum%10;
ocnum=ocnum/10;
foct=(foct*10)+temp;
}
printf("\nThe octal equivalent of %d\n",foct);
}

Answer / a jha

#include <stdio.h>
#include <conio.h>


int main()
{
int n,i=0,j=1,k=0;

printf("Enter the number:
");
scanf("%d",&n);
while(n !=0)
{
i = (n%8)*j;
n = n/8;
j= j*10;
k = k+i;

}


printf("%d",k);



getch();
return 0;
}

Answer / mayur anklekar

#include <stdio.h>
//Writer:Mayur Anklekar
int main()
{
int a,mod=0,b=0,u=1,c=1;
printf("Enter the Number:");
scanf("%d",&a);
while(a!=0)
{
mod=a%8;
u=mod*c;
b=b+u;
a=a/8;
c=c*10;
}
printf("Octal Equivalent=%d",b);
}

Happy Coding!!

Answer / priyankar kumar

Write a program to find the octal equivalent of the entered number
#include<stdio.h>
main()
{
int n,n1=0,n2=0,n3,a,b,c;
printf("enter the number in decimal
");
scanf("%d",&n);
c=n+1;
if((n%8)>0)
{
while(n>0)
{
a=n%8;
n1=n1*10+a;
n=n/8;
}
while(n1>0)
{
b=n1%10;
n2=n2*10+b;
n1=n1/10;
}
printf("octal equivalent=%d",n2);
}
else
{
while(c>0)
{
a=c%8;
n1=n1*10+a;
c=c/8;
}
while(n1>0)
{
b=n1%10;
n2=n2*10+b;
n1=n1/10;
}
n3=n2-1;
printf("octal number=%d
",n3);
}
getch();
}

Answer / gurpreet singh

#include<stdio.h>

int main()
{
int n,m,o=0,t=10;
printf("

Enter any integer value

");
scanf("%d",&n);

while(n>0)
{

m=n%8;
n=n/8;

o=o+(m*t);
t=t*10;

}
printf("

octal number=%d

",o/10);

}

Answer / priyankar kumar

//Write a program to find the octal equivalent of the entered number;
#include<stdio.h>
main()
{
int n,n1=0,n2=0,n3=0,n4=0,n5,a,b,c,d;
printf("enter the number in decimal
");
scanf("%d",&n);
c=n-1;
d=n+1;
if((n%8)>0)
{
while(n>0)
{
a=n%8;
n1=n1*10+a;
n=n/8;
}
n4=n1;
while(n1>0)
{
b=n1%10;
n2=n2*10+b;
n1=n1/10;
}
printf("octal equivalent=%d",n2);
}
else
{
while(c>0)
{
a=c%8;
n1=n1*10+a;
c=c/8;
}
while(n1>0)
{
b=n1%10;
n2=n2*10+b;
n1=n1/10;
}
while(d>0)
{
a= d%8;
n3=n3*10+a;
d=d/8;
}
while(n3>0)
{
b=n3%10;
n4=n4*10+b;
n3=n3/10;
}
n5=n2+(n4-n2)-1;
printf("octal number=%d
",n5);
}
getch();
}

Answer / mrityunjay barman

#include<conio.h>
#include<stdio.h>
#include<math.h>
void main()
{
int n,i=0,r,s=0;
printf("enter the number\n");
scanf("%d",&n);
while(n>0)
{r=n%8;
s=s+n*(pow(10,i));
n=n\8;
i++;
}
printf("the octal number =%d",s);
getch();
}

main() { if ((1||0) && (0||1)) { printf("OK I am done."); } else { printf("OK I am gone."); } } a. OK I am done b. OK I am gone c. compile error d. none of the above

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