Answer / raghuram.a

#include<iostream.h>
#include<conio.h>
int leap(int y)
{
if(y%4==0&&y%100!=0||y%400==0)
return 1;
else
return 0;
}
main()
{
int d,m,y,i,rem;
int a[12]={31,28,31,30,31,30,31,31,30,31,30,31};
long int days=0;
clrscr();
cout<<"enter date in dd/mm/yyyy format:";
cin>>d>>m>>y;
for(i=1;i<y;i++)
if(leap(i))
days+=366;
else
days+=365;
for(i=1;i<m;i++)
if(leap(y)&&i==2)
days+=29;
else
days+=a[i-1];
days+=d;
rem=days%7;
switch(rem)
{case 1:cout<<"monday";
break;
case 2:cout<<"tuesday";
break;
case 3:cout<<"wedday";
break;
case 4:cout<<"thursday";
break;
case 5:cout<<"friday";
break;
case 6:cout<<"saturday";
break;
case 0:cout<<"sunday";

}
getch();
return 0;
}

Answer / saurabh shah

Hey buddy wrong program....!!!

if you check with DOB : 16/4/1985 OR 16/04/1985

its showing Friday...

But if you check then right answer should be Tuesday ...

Answer / raghuram.a

No..it's giving Tuesday only..U enter 16 4 1985 n press enter.
It will show Tuesday only..Logic is correct.I made a mistake
by telling to enter date in dd/mm/yyyy format..but u just
enter date in dd mm yyyy format(space between dd,mm and
yyyy)..u will get correct ans.

Raghuram.A

Answer / abraham

Hi Raghu, thanks for your program.
can you try 29th of feb 1983 (29/02/1983). Actually such a
date is not present. But gives Tuesday.
May be you like to correct it.

Answer / raghuram.a

Well..Abraham..I am not checking for invalid dates in that
program.
Here is the program that u want..

#include<iostream.h>
#include<conio.h>
#include<stdio.h>

int leap(int y)
{
if(y%4==0&&y%100!=0||y%400==0)
return 1;
else
return 0;
}


int valid(int dd,int mm,int yy)
{
if(dd>31||dd<1||mm>12||mm<1||yy<0)
return 0;
if(mm<8)
if(mm%2==0&&dd>30)
return 0;
if(mm>=8)
if(mm%2!=0&&dd>30)
return 0;
if(mm==2)
{
if(yy%4==0&&dd>29)
return 0;
else
if(yy%4!=0&&dd>28)
return 0;
}
return 1;
}
main()
{
int d,m,y,i,rem;
int a[12]={31,28,31,30,31,30,31,31,30,31,30,31};
long int days=0;
clrscr();
cout<<"enter date in dd m yyyy format:";
scanf("%d %d %d",&d,&m,&y);
if(!valid(d,m,y))
{
cout<<"\nInvalid date";
getch();
return 0;
}

for(i=1;i<y;i++)
if(leap(i))
days+=366;
else
days+=365;
for(i=1;i<m;i++)
if(leap(y)&&i==2)
days+=29;
else
days+=a[i-1];
days+=d;
rem=days%7;
switch(rem)
{
case 1:cout<<"monday";
break;
case 2:cout<<"tuesday";
break;
case 3:cout<<"wedday";
break;
case 4:cout<<"thursday";
break;
case 5:cout<<"friday";
break;
case 6:cout<<"saturday";
break;
case 0:cout<<"sunday";
}
getch();
return 0;
}

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Answer / rose2502

@raghuram : you r too gud..thnx for the code..i m a student of class 12th and i have grt interest in computer language...but it seems i will never be able to acquire such a deepness in this subject :-(..

Answer / wellwisher

@Rose2502 : interest and working hard is the only key to
success..practise well:)

Answer / saumya

@raghuram:thnx 4 ur advice..i vl definitely follow it..bt seriously i m impressed wid ur deep knowledge in programming..i too want to be like u.

x=2 y=3 z=2 x++ + y++; printf("%d%d" x,y);

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